Use induction to prove: for any integer n > 1, (6j- 4) = 3n“ – n. j=1

Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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Use induction to prove: for any integer n > 1, (6j – 4) = 3n² – n.
j=1
Base case
1
> (6j – 4) =
3n – n =
n = 1
j= 1
Inductive step
k
Assume that for any k > 1
E (6j – 4) =
j= 1
k
we will prove that (6j – 4) =
j= 1
k
k
E (6j – 4) = > (6j – 4)+
j= 1
j= 1
%3D
By inductive hypothesis
k2+ 5
k+ 2
=( 3
k2+ 6
k+ 3
)-(k+ 1)
= 3 (k+1)^2
-(k + 1)
Transcribed Image Text:Use induction to prove: for any integer n > 1, (6j – 4) = 3n² – n. j=1 Base case 1 > (6j – 4) = 3n – n = n = 1 j= 1 Inductive step k Assume that for any k > 1 E (6j – 4) = j= 1 k we will prove that (6j – 4) = j= 1 k k E (6j – 4) = > (6j – 4)+ j= 1 j= 1 %3D By inductive hypothesis k2+ 5 k+ 2 =( 3 k2+ 6 k+ 3 )-(k+ 1) = 3 (k+1)^2 -(k + 1)
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