Use implicit differentiation to find dy/dx and d?y/dx?. x? + y? = 9 dy O A. x a?y y' dx2 x² + y? y3 dx dy O B. x d²y y' dx2 x+y? dx x dy x2-y y' dx2 Oc. dx ,2 dy x d?y x? + y? O D. dx y' dv2 2

Calculus: Early Transcendentals
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ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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**Problem Statement:**

Use implicit differentiation to find \( \frac{dy}{dx} \) and \( \frac{d^2y}{dx^2} \).

Equation:
\[ x^2 + y^2 = 9 \]

**Answer Choices:**

A. \(\frac{dy}{dx} = -\frac{x}{y}, \quad \frac{d^2y}{dx^2} = -\frac{x^2+y^2}{y^3}\)

B. \(\frac{dy}{dx} = -\frac{x}{y}, \quad \frac{d^2y}{dx^2} = -\frac{x+y^2}{y^3}\)

C. \(\frac{dy}{dx} = -\frac{x}{y}, \quad \frac{d^2y}{dx^2} = -\frac{y-x^2}{y^2}\)

D. \(\frac{dy}{dx} = -\frac{x}{y}, \quad \frac{d^2y}{dx^2} = \frac{x^2+y^2}{y^2}\)
Transcribed Image Text:**Problem Statement:** Use implicit differentiation to find \( \frac{dy}{dx} \) and \( \frac{d^2y}{dx^2} \). Equation: \[ x^2 + y^2 = 9 \] **Answer Choices:** A. \(\frac{dy}{dx} = -\frac{x}{y}, \quad \frac{d^2y}{dx^2} = -\frac{x^2+y^2}{y^3}\) B. \(\frac{dy}{dx} = -\frac{x}{y}, \quad \frac{d^2y}{dx^2} = -\frac{x+y^2}{y^3}\) C. \(\frac{dy}{dx} = -\frac{x}{y}, \quad \frac{d^2y}{dx^2} = -\frac{y-x^2}{y^2}\) D. \(\frac{dy}{dx} = -\frac{x}{y}, \quad \frac{d^2y}{dx^2} = \frac{x^2+y^2}{y^2}\)
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