Use implicit differentiation to find dy dx for the curve given by x²y + xy² = 6x.

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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**Implicit Differentiation Exercise**

**Problem Statement:**

Use implicit differentiation to find \(\frac{dy}{dx}\) for the curve given by the equation:

\[ x^2 y + xy^2 = 6x. \]

**Instructions:**

1. Differentiate both sides of the equation with respect to \(x\).
2. Apply the product rule to both \(x^2 y\) and \(xy^2\).
3. Collect all terms involving \(\frac{dy}{dx}\) on one side of the equation.
4. Solve for \(\frac{dy}{dx}\). 

Note: Make use of the product rule and chain rule where necessary since the equation involves variables on both sides.

This exercise is designed to help you understand the process of implicit differentiation, which is useful for finding derivatives of functions that are not explicitly solved for one variable in terms of another.
Transcribed Image Text:**Implicit Differentiation Exercise** **Problem Statement:** Use implicit differentiation to find \(\frac{dy}{dx}\) for the curve given by the equation: \[ x^2 y + xy^2 = 6x. \] **Instructions:** 1. Differentiate both sides of the equation with respect to \(x\). 2. Apply the product rule to both \(x^2 y\) and \(xy^2\). 3. Collect all terms involving \(\frac{dy}{dx}\) on one side of the equation. 4. Solve for \(\frac{dy}{dx}\). Note: Make use of the product rule and chain rule where necessary since the equation involves variables on both sides. This exercise is designed to help you understand the process of implicit differentiation, which is useful for finding derivatives of functions that are not explicitly solved for one variable in terms of another.
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