Use implicit differentiation to find and .Assume that the equation defines z as a differentia ôy function near each (x, y). xyz = sin(7x + 5y + 2z) 7cos(7x + 5y + 2z) – 4ry*z xy4 – 2cos(7x + 5y + 2z) ôz _ 5cos(7x + 5y + 2z) – 4xʻ³z ôy O A. xy – 2cos(7x + 5y + 2z) ôz_ 5cos(7x + 5y + 2z) – 4xy°z xy4 – 2cos(7x + 5y + 2z) ôz_ 7cos(7x + 5y + 2z) – 4x°y*z ôy OB. xy – 2cos(7x + 5y + 2z) 4.4 OC. ôz_ 7cos(7x + 5y + 2z) – 4xy*z xy - 2cos(7x + 5y + 2z) ôz_ 5cos(7x + 5y + 2z) – 4x*y°z y - 2cos(7x + 5y + 2z) ôx OD. 5cos(7x + 5y + 2z) – 4xy°z xy - 2cos(7x + 5y + 2z) ôz_ 7cos(7x + 5y + 22) – 4xy*z ôy xy - 2cos(7x + 5y + 2z) ôx
Use implicit differentiation to find and .Assume that the equation defines z as a differentia ôy function near each (x, y). xyz = sin(7x + 5y + 2z) 7cos(7x + 5y + 2z) – 4ry*z xy4 – 2cos(7x + 5y + 2z) ôz _ 5cos(7x + 5y + 2z) – 4xʻ³z ôy O A. xy – 2cos(7x + 5y + 2z) ôz_ 5cos(7x + 5y + 2z) – 4xy°z xy4 – 2cos(7x + 5y + 2z) ôz_ 7cos(7x + 5y + 2z) – 4x°y*z ôy OB. xy – 2cos(7x + 5y + 2z) 4.4 OC. ôz_ 7cos(7x + 5y + 2z) – 4xy*z xy - 2cos(7x + 5y + 2z) ôz_ 5cos(7x + 5y + 2z) – 4x*y°z y - 2cos(7x + 5y + 2z) ôx OD. 5cos(7x + 5y + 2z) – 4xy°z xy - 2cos(7x + 5y + 2z) ôz_ 7cos(7x + 5y + 22) – 4xy*z ôy xy - 2cos(7x + 5y + 2z) ôx
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Transcribed Image Text:Use implicit differentiation to find
and
Assume that the equation defines z as a differentiable
function near each (x, y).
= 2.
xz= sin(7x + 5y + 27)
ôz_ 7cos(7x + 5y + 2z) – 4xyz
x4– 2cos(7x + 5y + 2z)
5cos(7x + 5y + 2z) – 4xz
x4 – 2cos(7x + 5y + 2z)
A.
ôy
ôz_ 5cos(7x + 5y + 2z) – 4xy°z
x4– 2cos(7x + 5y + 2z)
ôz_ 7cos(7x + 5y + 22) – 4xy*z
ôy
B.
ôx
xy – 2cos(7x + 5y + 2z)
OC.
7cos(7x + 5y + 2z) – 4ry*z
y - 2cos(7x + 5y + 2z)
ôz _ 5cos(7x + 5y + 2z) – 4xʻ°z
ôy
xy - 2cos(7x + 5y + 2z)
OD.
5cos(7x + 5y + 2) – 4x°z
x*y – 2cos(7x + 5y + 2z)
ôz_ 7cos(7x + 5y + 2z) – 4x°y*z
y - 2cos(7x + 5y + 2z)
ôy
||
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