Use Ideal gas law equation to solve the problem. Fermentation of glucose produce gas in the form of carbon dioxide, how many moles of carbon dioxide is produced if 0.78 L of carbon dioxide at 293K and 1.00 atm was collected during the process?

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Use Ideal gas law equation to solve the problem.

Fermentation of glucose produce gas in the form of carbon dioxide, how many moles of carbon dioxide is
produced if 0.78 L of carbon dioxide at 293K and 1.00 atm was collected during the process?

## Ideal Gas Law

The Ideal Gas Law is a relationship that illustrates the correlations among the pressure, temperature, volume, and the number of moles of a gas. By combining the three fundamental gas laws (Boyle’s Law, Charles’ Law, and Avogadro’s Law), we obtain the equation:

\[ PV = nRT \]

where:
- \( P \) = pressure of the gas
- \( V \) = volume of the gas
- \( n \) = number of moles of the gas
- \( R \) = universal gas constant (\(0.0821\, \text{L atm} / \text{mol K}\))
- \( T \) = temperature in Kelvin (K)

### Sample Problem:

**Problem Statement:**
1. A sample of liquid acetone is placed in a 0.025 L flask and vaporized by heating it to 75°C at 1.02 atm. The vapor weighs 5.87 g. Calculate the number of moles of acetone.

**Given Data:**
- Volume (\( V \)) = 0.025 L
- Temperature (\( T \)) = \( 75^\circ \text{C} + 273 = 348 \text{K} \)
- Pressure (\( P \)) = 1.02 atm
- Universal Gas Constant (\( R \)) = 0.0821 L atm / mol K

**Unknown:**
- Number of moles (\( n \)) = ?

**Formula:**
\[ n = \frac{PV}{RT} \]

**Solution:**
\[ n = \frac{(1.02\, \text{atm}) (0.025\, \text{L})}{(0.0821\, \text{L atm} / \text{mol K}) (348\, \text{K})} \]

Calculating the values:
\[ n = \frac{0.0255}{28.5948} \approx 0.00089 \text{mole} \]

**Answer:**
\[ n = 0.00089 \text{mole} \]
Transcribed Image Text:## Ideal Gas Law The Ideal Gas Law is a relationship that illustrates the correlations among the pressure, temperature, volume, and the number of moles of a gas. By combining the three fundamental gas laws (Boyle’s Law, Charles’ Law, and Avogadro’s Law), we obtain the equation: \[ PV = nRT \] where: - \( P \) = pressure of the gas - \( V \) = volume of the gas - \( n \) = number of moles of the gas - \( R \) = universal gas constant (\(0.0821\, \text{L atm} / \text{mol K}\)) - \( T \) = temperature in Kelvin (K) ### Sample Problem: **Problem Statement:** 1. A sample of liquid acetone is placed in a 0.025 L flask and vaporized by heating it to 75°C at 1.02 atm. The vapor weighs 5.87 g. Calculate the number of moles of acetone. **Given Data:** - Volume (\( V \)) = 0.025 L - Temperature (\( T \)) = \( 75^\circ \text{C} + 273 = 348 \text{K} \) - Pressure (\( P \)) = 1.02 atm - Universal Gas Constant (\( R \)) = 0.0821 L atm / mol K **Unknown:** - Number of moles (\( n \)) = ? **Formula:** \[ n = \frac{PV}{RT} \] **Solution:** \[ n = \frac{(1.02\, \text{atm}) (0.025\, \text{L})}{(0.0821\, \text{L atm} / \text{mol K}) (348\, \text{K})} \] Calculating the values: \[ n = \frac{0.0255}{28.5948} \approx 0.00089 \text{mole} \] **Answer:** \[ n = 0.00089 \text{mole} \]
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