Use Green's Theorem to find the counterclockwise circulation and outward flux for the field F = (8x - 9y)i + (7y - 9x)j and curve C: the square bounded by x=0, x=8, y = 0, y = 8. The flux is (Simplify your answer.)

Algebra and Trigonometry (MindTap Course List)
4th Edition
ISBN:9781305071742
Author:James Stewart, Lothar Redlin, Saleem Watson
Publisher:James Stewart, Lothar Redlin, Saleem Watson
Chapter9: Vectors In Two And Three Dimensions
Section9.FOM: Focus On Modeling: Vectors Fields
Problem 11P
icon
Related questions
Question

Q4

### Use of Green's Theorem to Calculate Flux and Circulation

#### Problem Statement
Use Green's Theorem to find the counterclockwise circulation and outward flux for the field **F = (8x − 9y)i + (7y − 9x)j** and curve **C**: the square bounded by **x = 0**, **x = 8**, **y = 0**, **y = 8**.

---

#### Calculation Steps

---

**Question:** Calculate the outward flux:

The outward flux is **[Input Box]**.
*(Simplify your answer.)*

---

Green's Theorem relates a line integral around a simple closed curve **C** and a double integral over the plane region **D** bounded by **C**. It states:

**∮C (P dx + Q dy) = ∬D ( (∂Q/∂x - ∂P/∂y) dA )**

Given: 
- **P = 8x - 9y**
- **Q = 7y - 9x**

Use the partial derivatives:
- **∂Q/∂x = ∂/∂x (7y - 9x) = -9**
- **∂P/∂y = ∂/∂y (8x - 9y) = -9**

The integrand becomes:
- **∂Q/∂x - ∂P/∂y = -9 - (-9) = 0**

Since the integrand is 0, the double integral of 0 over any region is 0, hence:

**∬D 0 dA = 0**

Thus, the outward flux around the given curve C is **0**.
Transcribed Image Text:### Use of Green's Theorem to Calculate Flux and Circulation #### Problem Statement Use Green's Theorem to find the counterclockwise circulation and outward flux for the field **F = (8x − 9y)i + (7y − 9x)j** and curve **C**: the square bounded by **x = 0**, **x = 8**, **y = 0**, **y = 8**. --- #### Calculation Steps --- **Question:** Calculate the outward flux: The outward flux is **[Input Box]**. *(Simplify your answer.)* --- Green's Theorem relates a line integral around a simple closed curve **C** and a double integral over the plane region **D** bounded by **C**. It states: **∮C (P dx + Q dy) = ∬D ( (∂Q/∂x - ∂P/∂y) dA )** Given: - **P = 8x - 9y** - **Q = 7y - 9x** Use the partial derivatives: - **∂Q/∂x = ∂/∂x (7y - 9x) = -9** - **∂P/∂y = ∂/∂y (8x - 9y) = -9** The integrand becomes: - **∂Q/∂x - ∂P/∂y = -9 - (-9) = 0** Since the integrand is 0, the double integral of 0 over any region is 0, hence: **∬D 0 dA = 0** Thus, the outward flux around the given curve C is **0**.
Expert Solution
steps

Step by step

Solved in 3 steps

Blurred answer
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
Algebra and Trigonometry (MindTap Course List)
Algebra and Trigonometry (MindTap Course List)
Algebra
ISBN:
9781305071742
Author:
James Stewart, Lothar Redlin, Saleem Watson
Publisher:
Cengage Learning