Use Green's Theorem to calculate the circulation of F = 3xyi around the rectangle 0 ≤ x ≤ 2,0 ≤ y ≤ 3 oriented counterclockwise. , circulation =

Advanced Engineering Mathematics
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Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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**Title: Calculating Circulation Using Green's Theorem**

**Objective:** 
To calculate the circulation of the vector field \(\vec{F} = 3xy \vec{i}\) around the rectangle defined by \(0 \leq x \leq 2, 0 \leq y \leq 3\), oriented counterclockwise.

**Instructions:**

Use Green's Theorem, which relates a line integral around a simple closed curve \(C\) to a double integral over the plane region \(D\) bounded by \(C\).

**Formula:**

Green's Theorem can be stated as:
\[
\oint_C \vec{F} \cdot d\vec{r} = \iint_D \left( \frac{\partial N}{\partial x} - \frac{\partial M}{\partial y} \right) \, dA
\]
where \(\vec{F} = M\vec{i} + N\vec{j}\).

For \(\vec{F} = 3xy\vec{i}\), we have:
- \(M = 3xy\)
- \(N = 0\)

To find the circulation, we calculate:
\[
\frac{\partial N}{\partial x} - \frac{\partial M}{\partial y} = 0 - 3x
\]

**Calculation Domain:**

Integrate over the rectangle defined by \(0 \leq x \leq 2\) and \(0 \leq y \leq 3\).

**Solution:**

Evaluate the double integral:
\[
\iint_D -3x \, dA = \int_0^3 \int_0^2 (-3x) \, dx \, dy
\]

Perform the integration, and calculate the circulation.

**Conclusion:**

Fill in the calculated circulation:
\[
\text{circulation} = \boxed{}
\]

**Notes:**
- Ensure calculations are accurate.
- Remember that the vector field has only one nonzero component.
Transcribed Image Text:**Title: Calculating Circulation Using Green's Theorem** **Objective:** To calculate the circulation of the vector field \(\vec{F} = 3xy \vec{i}\) around the rectangle defined by \(0 \leq x \leq 2, 0 \leq y \leq 3\), oriented counterclockwise. **Instructions:** Use Green's Theorem, which relates a line integral around a simple closed curve \(C\) to a double integral over the plane region \(D\) bounded by \(C\). **Formula:** Green's Theorem can be stated as: \[ \oint_C \vec{F} \cdot d\vec{r} = \iint_D \left( \frac{\partial N}{\partial x} - \frac{\partial M}{\partial y} \right) \, dA \] where \(\vec{F} = M\vec{i} + N\vec{j}\). For \(\vec{F} = 3xy\vec{i}\), we have: - \(M = 3xy\) - \(N = 0\) To find the circulation, we calculate: \[ \frac{\partial N}{\partial x} - \frac{\partial M}{\partial y} = 0 - 3x \] **Calculation Domain:** Integrate over the rectangle defined by \(0 \leq x \leq 2\) and \(0 \leq y \leq 3\). **Solution:** Evaluate the double integral: \[ \iint_D -3x \, dA = \int_0^3 \int_0^2 (-3x) \, dx \, dy \] Perform the integration, and calculate the circulation. **Conclusion:** Fill in the calculated circulation: \[ \text{circulation} = \boxed{} \] **Notes:** - Ensure calculations are accurate. - Remember that the vector field has only one nonzero component.
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