Use Euler's method to obtain a four-decimal approximation of the indicated value. Carry out the recursion of (3) in Section 2.6 Yn + 1 = Yn + hf(Xn, Yn) (3) by hand, first using h = 0.1 and then using h = 0.05. y' = 2x - 3y + 1, y(1) = 2; y(1.2) y(1.2) y(1.2) (h = 0.1) (h = 0.05)

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Chapter2: Second-order Linear Odes
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Discrete Math

 

**Euler's Method for Approximating Solutions to Differential Equations**

To approximate the solution of a differential equation using Euler's Method, follow these steps:

1. **Equation and Initial Conditions:**
   - Differential Equation: \( y' = 2x - 3y + 1 \)
   - Initial Condition: \( y(1) = 2 \)

2. **Objective:**
   - Estimate \( y(1.2) \) with two different step sizes:
      - \( h = 0.1 \)
      - \( h = 0.05 \)

3. **Euler's Formula:**
   \[
   y_{n+1} = y_n + h \cdot f(x_n, y_n)
   \]
   Here, \( f(x, y) = 2x - 3y + 1 \).

4. **Procedure:**
   - Start with the initial condition \( (x_0, y_0) \) = (1, 2).
   - Use the step size \( h \) to increment \( x \).
   - Calculate successive \( y \) values using Euler's formula.

5. **Calculations:**

   - **For \( h = 0.1 \):**

     - Calculate \( y \) at \( x = 1.1 \).
     - Then calculate \( y \) at \( x = 1.2 \).

   - **For \( h = 0.05 \):**

     - Calculate \( y \) at \( x = 1.05 \).
     - Continue to \( x = 1.1 \), then \( 1.15 \), and finally \( 1.2 \).

6. **Boxes for Solutions:**

   - \( y(1.2) \approx \) \[\boxed{}\]  *(when \( h=0.1 \))*

   - \( y(1.2) \approx \) \[\boxed{}\]  *(when \( h=0.05 \))*

**Note:** The detailed calculations can be filled in the boxes using the above method step-by-step.
Transcribed Image Text:**Euler's Method for Approximating Solutions to Differential Equations** To approximate the solution of a differential equation using Euler's Method, follow these steps: 1. **Equation and Initial Conditions:** - Differential Equation: \( y' = 2x - 3y + 1 \) - Initial Condition: \( y(1) = 2 \) 2. **Objective:** - Estimate \( y(1.2) \) with two different step sizes: - \( h = 0.1 \) - \( h = 0.05 \) 3. **Euler's Formula:** \[ y_{n+1} = y_n + h \cdot f(x_n, y_n) \] Here, \( f(x, y) = 2x - 3y + 1 \). 4. **Procedure:** - Start with the initial condition \( (x_0, y_0) \) = (1, 2). - Use the step size \( h \) to increment \( x \). - Calculate successive \( y \) values using Euler's formula. 5. **Calculations:** - **For \( h = 0.1 \):** - Calculate \( y \) at \( x = 1.1 \). - Then calculate \( y \) at \( x = 1.2 \). - **For \( h = 0.05 \):** - Calculate \( y \) at \( x = 1.05 \). - Continue to \( x = 1.1 \), then \( 1.15 \), and finally \( 1.2 \). 6. **Boxes for Solutions:** - \( y(1.2) \approx \) \[\boxed{}\] *(when \( h=0.1 \))* - \( y(1.2) \approx \) \[\boxed{}\] *(when \( h=0.05 \))* **Note:** The detailed calculations can be filled in the boxes using the above method step-by-step.
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