Use Cramer's rule to solve the system. X1 + X2 = 5 - 5x1 4x3 = 0 X2 - 4x3 = 4 Xg = (Type integers or simplified fractions.)

Q: Multiply both sides by (x² + 1)² and combine like terms. x² + 6x + 1 = (Ax + B)(x² + 1) + Cx + D =…

A: The given equation

Q: 3(2x+2)-3x=6+3

A: Given query is to find the value of x.

Q: 4a(7a²-5a-7)+8a³+4a²+4a-15 For a = -3

A: To evalaute the value of given expression at the given value of a.

Q: (3x+5y)2

A: ANSWER :

Q: Multiply. (a - 5)(2a + 7) (a - 5)(2a + 7) = (Simplify your answer.)

A:

Q: 12x-2(4x+5)

A:

Q: 26n - 7m + 4 (10n- 6m)

A: We have to simply

Q: The equation is 6n-3, not 6n-1

A:

Q: 2(x+3)-3(x+4)=-x+18

A: Solve and find solution:

Q: a+2b+4c+3d=21 -3a+4b-2c+3d=-1 a+6c+3d=-19 3a+4b-3c-2d=16

A:

Q: Does -3(4n + 2) = 4n + -2(4n - 6) have a solution or no

A: We have to find whether this equation has solution or not. The given expression is -3(4n + 2) = 4n +…

Q: 2. (x-11)(5x-4)(x-3)

A:

Q: x3 +6x2 over x2+2x-24

A:

Q: ind (2× - 7)²

A: Given: 2x-72

Q: divide (m4 - 10m3 + 12m2 + 21m + 23) ̧(m - 3)

A:

Q: Multiply. (7x²+1) (4x²+5)

A: The given expression is,

Q: 5(2x - 1) + 1 = 2x - 4 + 8x

A:

Q: Multiply. (9x³ + 4) (6x² + 7x + 5) (9x3 = O +4) (6x² + 7x +5) (Simplify your answer.)

A:

Q: (6x−1)(3x+2)

A: Given: To simplify the expression (6x−1)(3x+2)

Q: X - 6 x2 - 6x + 8 Jo

A:

Q: (a²-3ab+2b²)+(-4a²+5ab-b²)

A:

Q: 5(22x+1) = 8x

A:

Q: 6x-40=2(x+8)

A:

Q: (2x+4xn-1)+(-3x+5xn+3)

A: Gicen,          2x+4xn-1+-3x+5xn+3

Q: x(2+3x)4(4x-2)

A: Here we simplify the given equation x(2+3x)4(4x-2).

Q: 2x+34=4(x+5)

A: Here we will solve for x,

Q: x x-4 + 3x+10 2x²-5x-12 2x+3

A:

Q: S 3+4x+3 dx x4-5x2+4 5.

A: Here, x3+4x+3x4-5x2+4=x3+4x+3(x2-1)(x2-4)⇒x3+4x+3x4-5x2+4=x3+4x+3(x-1)(x+1)(x-2)(x+2)

Q: x² - 5x + 6.+3 x² -9 5x-10 and write the answer in simplest form

A: Given: x2-5x+6x2-9×x+35x-10 To multiply the answer and write in simplest form.

Q: 2x•(3x+2)

A: Find the product 2x•(3x+2)

Q: -2w-6(-6x+w)+6x

A: To simplify the following expression.-2w-6-6x+w+6x

Q: 3x5-2x2+1 x3

A: ∫3x5-2x2+1x3dx=x3-2ln(x)-12x2+C    where C be the integral constant.

Q: 3(2x + 2) – 3x = 6 + 3x %3D

A: Given :                     3(2x+2) - 3x = 6 + 3x

Q: 2x2 + 3x – 20 = 0

A:

Q: (3a-2b)(3a+2b)

A: The given expression is: (3a-2b)(3a+2b)

Q: Divide. (x³ – x²-4x² 4x +5x-2) - (X-1)

A: The given expression x3-4x2+5x-2÷x-1

Q: (2x² + 3x-7)+(3x²+x+9)

A: Here we have to add the 2 expressions.