Use continuity to evaluate the limit. 12 + Vx lim x-4 V12 + x Step 1 Consider the intervals for which the numerator and the denominator are continuous. The numerator 12 + Vx is continuous on the interval |(-00,00) x The denominator V12 + x is continuous and nonzero on the interval (-0, – 12) U (-12,00) x

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