Use constant specific heats at room temperature in solving the problem. An air-standard cycle with variable specific heats is executed in a closed system with 0.005 kg of air and consists of the following three processes: 1-2 v constant heat addition from 95 kPa and 18°C to 375 kPa 2-3 Isentropic expansion to 95 kPa 3-1 P = constant heat rejection to initial state (a) Show the cycle on P-v and T-s diagrams. (b) Calculate the net work per cycle, in kJ. (c) Determine the thermal efficiency.

Elements Of Electromagnetics
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Author:Sadiku, Matthew N. O.
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1. Use constant specific heats at room temperature in solving the problem.
An air-standard cycle with variable specific heats is executed in a closed system with
0.005 kg of air and consists of the following three processes:
1-2 v= constant heat addition from 95 kPa and 18°C to 375 kPa
2-3 Isentropic expansion to 95 kPa
3-1 P = constant heat rejection to initial state
(a) Show the cycle on P-v and T-s diagrams.
(b) Calculate the net work per cycle, in kJ.
(c) Determine the thermal efficiency.
Transcribed Image Text:1. Use constant specific heats at room temperature in solving the problem. An air-standard cycle with variable specific heats is executed in a closed system with 0.005 kg of air and consists of the following three processes: 1-2 v= constant heat addition from 95 kPa and 18°C to 375 kPa 2-3 Isentropic expansion to 95 kPa 3-1 P = constant heat rejection to initial state (a) Show the cycle on P-v and T-s diagrams. (b) Calculate the net work per cycle, in kJ. (c) Determine the thermal efficiency.
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