Use calculus to show that the maximum possible area of a triangle with one vertex at (0, 0) and the other two on the positive y-axis and the negative x-axis where the diagonal has length L = 3, occurs when the angles at both (other) vertices are π/4. Include a sketch.

Q: Consider a parabolic arch whose shape may be represented by the graph of y = 9 - x2, where the base…

A: Pick a point P at the considered arc,  that is                         p = x , 9-x2…

Q: A rectangle is bounded by the x-axis and the parabola y=9-x². What length and width should the…

A: Solution :-   Given,A rectangle is bounded by the x-axis and the parabola y=9-x2Since, y aixs is the…

Q: The shortest distance from (−7,6,−8) to the xy-plane is

A: Since the plane is a xy-plane so, the point will be (-7,6,0).

Q: Find the distance between two points (1, 2) and (3, −1).

A: We want to find the distance between the given two points. We use formula for finding the distance…

Q: ind point P and Q on the parabola y=(-x^2)+1 so that the triangle ABC formed by the x-axis and the…

A: Given that the curve is                         To find point P and Q on the given parabola, so that…

Q: To y=x²-12x + 20 Parabola Wite the intersection point of the tanpent lines drawn from (2,0) and…

A: Consider the given parabola and find the derivative of the parabola.…

Q: The parabola y = Px² + Qx + R_passes through the coordinate (1,1) and has b. Determine the values of…

A:

Q: Find the shortest distance of the point (10,4) to the parabola y=x2

A: Consider a  point on parabola  y=x2. Distance of this point with (10,4) s2=(x-10)2+(y-4)2…