Use balanced chemical equations to relate amounts of reactants and products. The unbalanced equation for the reaction between perchloric acid (HCIO4) and tetraphosphorus decaoxide is shown below. Balance the equation (enter the smallest integer possible in each box, including the integer "1" when needed) and determine the amount of P4010 consumed and the amounts of H3PO4 and CI₂07 produced when 0.805 mol of HCIO4 reacts. HCIO4 (aq) + P4010 (S)- mol P4010 consumed mol H3PO4 produced mol Cl₂O7 produced H3PO4 (aq) + CL,O, (I)

Use balanced chemical equations to relate amounts of reactants and products. The unbalanced equation for the reaction between perchloric acid (HCIO4) and tetraphosphorus decaoxide is shown below. Balance the equation (enter the smallest integer possible in each box, including the integer "1" when needed) and determine the amount of P4010 consumed and the amounts of H3PO4 and CI₂07 produced when 0.805 mol of HCIO4 reacts. HCIO4 (aq) + P4010 (S)- mol P4010 consumed mol H3PO4 produced mol Cl₂O7 produced H3PO4 (aq) + CL,O, (I)

Chemistry: The Molecular Science

5th Edition

ISBN:9781285199047

Author:John W. Moore, Conrad L. Stanitski

Publisher:John W. Moore, Conrad L. Stanitski

Chapter3: Chemical Reactions

Section: Chapter Questions

Problem 81QRT: Write the balanced chemical equation for the complete combustion of adipic acid, an organic acid...

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Concept explainers

Stoichiometry

Stoichiometry is a chemical division that evaluates the quantitative content of the chemical process with the help of the reacting molecules or products taking part in the reaction. The term “stoicheion” in “Stoichiometry”, is an old Greek term for "element" whereas “metron” means "measure".

Question

Use balanced chemical equations to relate amounts of reactants and products.
The unbalanced equation for the reaction between perchloric acid (HCIO4) and tetraphosphorus decaoxide is
shown below.
Balance the equation (enter the smallest integer possible in each box, including the integer "1" when needed)
and determine the amount of P4010 consumed and the amounts of H3PO4 and Cl₂07 produced when 0.805 mol
of HCIO4 reacts.
HCIO4 (aq) +
P4010 (S)
mol P4010 consumed
mol H3PO4 produced
mol Cl₂O7 produced
H3PO4 (aq) +
Cl₂07 (1)

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