USE APPROXIMATE ANALYSIS USE 2 decimal places. no commas. Given: Single-stage, voltage-divider biased. common-emitter with 1. VCC = 14V 2. R1 = 37kohms 3. R2 = 10kohms 4. RC = 4kohms 5. RE = 1kohms 6. RS = 60hms 7. RL = 2kohms 8. BDC = BAC = 144 9. ** 10.C, andc, are coupling capacitors. 11.Cg is bypass capacitor 12. 13.Solve for: a. VB = Blank 1 V: b. VE = Blank 2 V: C. IE = Blank 3 mA; d. VCE = Blank 4 V: e. VC = Blank 5 V: f. re' = Blank 6 ohms: 8. Rin(base) = Blank 7 kohms : h. Rințtot) = Blank 8 kohms : I. Voltage gain (Av) = Blank 9 ; j. Attenuation (Att) = Blank 1o: k. Overall voltage gain (AVT) = Blank 11:

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USE APPROXIMATE ANALYSIS
USE 2 decimal places, no commas.
Given:
Single-stage, voltage-divider biased, common-emitter with
1. VCC = 14V
2. R1 = 37kohms
3. R2 = 10kohms
4. RC = 4kohms
5. RE = 1kohms
6. RS = 6ohms
7. RL = 2kohms
8. BDC = BAC = 144
9. **
10.C, andcz are coupling capacitors.
11.C3 is bypass capacitor
12.
13.Solve for:
a. VB = Blank 1 V:
b. VE = Blank 2 V:
C. IE = Blank 3 mA ;
d. VCE = Blank 4 V;
e. VC = Blank 5 V:
f. re' = Blank 6 ohms:
8. Rin(base) = Blank 7 kohms ;
h. Rin(tot) = Blank 8 kohms :
i. Voltage gain (Av) = Blank 9;
j. Attenuation (Att) = Blank 10;
k. Overall voltage gain (AVT) = Blank 11:
%3D
Transcribed Image Text:USE APPROXIMATE ANALYSIS USE 2 decimal places, no commas. Given: Single-stage, voltage-divider biased, common-emitter with 1. VCC = 14V 2. R1 = 37kohms 3. R2 = 10kohms 4. RC = 4kohms 5. RE = 1kohms 6. RS = 6ohms 7. RL = 2kohms 8. BDC = BAC = 144 9. ** 10.C, andcz are coupling capacitors. 11.C3 is bypass capacitor 12. 13.Solve for: a. VB = Blank 1 V: b. VE = Blank 2 V: C. IE = Blank 3 mA ; d. VCE = Blank 4 V; e. VC = Blank 5 V: f. re' = Blank 6 ohms: 8. Rin(base) = Blank 7 kohms ; h. Rin(tot) = Blank 8 kohms : i. Voltage gain (Av) = Blank 9; j. Attenuation (Att) = Blank 10; k. Overall voltage gain (AVT) = Blank 11: %3D
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