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Use appropriate Lagrange interpolating polynomials of degrees three to approximate f(8.4) if f(8.1) = 16.94410, f(8.3) = 17.56492, f(8.6) = 18.50515, and f(8.7) %3D = 18.82091 O P3(x)=0.002083333334x^3+0.1120833334x^2+1.686 2.96077250 O P3(x)=0.002083333334x^3+0.1120833334x^2-4.686 5.96077250 O P3(x)=0.002083333334x^3+0.1120833334x^2+6.686 4.96077250 O P3(x)=1.002083333334x^3+0.1120833334x^2+22.68 2.96077250

Use appropriate Lagrange interpolating polynomials of degrees three to approximate f(8.4) if f(8.1) = 16.94410, f(8.3) = 17.56492, f(8.6) = 18.50515, and f(8.7) %3D = 18.82091 O P3(x)=0.002083333334x^3+0.1120833334x^2+1.686 2.96077250 O P3(x)=0.002083333334x^3+0.1120833334x^2-4.686 5.96077250 O P3(x)=0.002083333334x^3+0.1120833334x^2+6.686 4.96077250 O P3(x)=1.002083333334x^3+0.1120833334x^2+22.68 2.96077250

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Use appropriate Lagrange interpolating polynomials of degrees three to approximate f(8.4) if f(8.1) = 16.94410, f(8.3) = 17.56492, f(8.6) = 18.50515, and f(8.7) = 18.82091 O P3(x)=0.002083333334x^3+0.1120833334x^2+1.686: 2.96077250 O P3(x)=0.002083333334x^3+0.1120833334x^2-4.6862 5.96077250 O P3(x)=0.002083333334x^3+0.1120833334x^2+6.686: 4.96077250 O P3(x)=1.002083333334x^3+0.1120833334x^2+22.68 2.96077250
Transcribed Image Text:Use appropriate Lagrange interpolating polynomials of degrees three to approximate f(8.4) if f(8.1) = 16.94410, f(8.3) = 17.56492, f(8.6) = 18.50515, and f(8.7) = 18.82091 O P3(x)=0.002083333334x^3+0.1120833334x^2+1.686: 2.96077250 O P3(x)=0.002083333334x^3+0.1120833334x^2-4.6862 5.96077250 O P3(x)=0.002083333334x^3+0.1120833334x^2+6.686: 4.96077250 O P3(x)=1.002083333334x^3+0.1120833334x^2+22.68 2.96077250
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