Current Attempt in ProgressUse a t-distribution to find a confidence interval for the difference in means using the relevant sample results from paired data.Assume the results come from random samples from populations that are approximately normally distributed, and that differences arecomputed using d = x₁ = x₂A 99% confidence interval for using the paired data in the following table:best estimate-margin of error=CaseThe 99% confidence interval is iTreatment1Treatment21 2321 28 30 244Give the best estimate for the margin of error, and the confidence interval.Enter the exact answer for the best estimate, and round your answers for the margin of error and the confidence interval to twodecimal places.toi518 31 25 22 2128

We have given a paired data set as follows: CaseTreatment 1Treatment 21211822831330254242252821We…

Answered: Use a t-distribution to find a…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Sales personnel for Skillings Distributors submit weekly reports listing the customer contacts made during the week. A sample of 85 weekly reports showed a sample mean of 18.5 customer contacts per week. The sample standard deviation was 5.4. Provide 90% and 95% confidence intervals for the population mean number of weekly customer contacts for the sales personnel. 90% confidence interval, to 2 decimals: 95% confidence interval, to 2 decimals:
We have developed a new drug used to reduce fever and want to test its efficacy. Ten ER patients who are running a fever agree to take the new drug instead of the traditional treatment. Their temperatures are taken before the drug is administered and 30 minutes after taking the drug. The results are recorded in the Excel file below. Use the data to construct and interpret a 99% confidence interval for the mean change in temperatures of patients after taking this drug using Excel. Be sure to include any explanation necessary along with a sentence that explains what the interval means. First Temp Second Temp 100.1 98.9 101.3 99.1 102.1 99.2 102.7 99 101.9 98.7 100.8 98.6 103.1 99.4 102.5 99.2 103.5 100.1 101.7 99.2
na test of the effectiveness of garlic for lowering cholesterol, 47 subjects were treated with garlic in a processed tablet form. Cholesterol levels were measured before and after the treatment. The changes (before - after) in their levels of LDL cholesterol (in mg/dL) have a mean of 3.4 and a standard deviation of 19.8. Construct a 95% confidence interval estimate of the mean net change in LDL cholesterol after the garlic treatment. What does the confidence interval suggest about the effectiveness of garlic in reducing LDL cholesterol? Click here to view a t distribution table. Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table. What is the confidence interval estimate of the population mean µ? Omg/dL
A random sample of 500 males included 215 that approved of the performance of a President. A random sample of 500 females included 185 that approved of the performance of a President. Determine each of the following parts that will lead you to construct a 95% confidence interval for the overall difference in the percentage of males and females that approve of the President's performance. group one males, gorup 2 females Calculate E, the margin of error, for a 95% level of confidence, Create the final confidence interval for the difference in percentages
Why do we use a t-distribution to compute confidence intervals for population means?
The Pizza Shop wanted to determine what proportion of its customers ordered only cheese pizza. Out of 80 customers surveyed, 15 ordered cheese pizza. They want a 99% confidence interval of the true proportion of customers who order only cheese pizza. Which type of confidence interval should we use here? a confidence interval for the mean using a table value from the standard normal distribution. a confidence interval for the mean using a table value from the t distribution. a confidence interval for a proportion using a table value from the standard normal distribution. a confidence interval for proportion using a table value from the t distribution.
Match to the appropriate answer. You will not use all options and you may not use each option more than once. Dummy variable Coefficient (beta) Correlation coefficient Heteroscedasticity p-value R² + Residual A. Used with categorical variable B. Lower value means statistical significance at a higher confidence level. C. When the distribution of residuals does change as the independent variable changes. D. Higher value means statistical significance at a higher confidence level. E. Difference between the predicted and observed values. F. When the distribution of residuals does not change as the independent variable changes. G. Min=-1, Max=1 H. Min-0, Max=1 1. Used to determine how much dependent variables changes if independent variable changed.
Using the t-table, find the critical value for a left-tailed test with a significance level of 10% and a sample size of 25.
Use the given confidence interval to find the margin of error and the sample mean. (13.2,20.6) The sample mean is The margin of error is (Type an integer or a decimal ) (Type an integer or a decimal)
The accompanying data represent the running times of files produced by two motion-picture companies. Assume that the running-time differences are approximately normally distributed. Construct a 90% confidence interval for 90% confidence interval for μ - μ were created, should it be assumed that o² = = If a Company | 106 96 105 Time (minutes) 91 99 II 101 78 123 89 171 89 120 Click here to view page 1 of the table of critical values of the F-distribution, for alpha = 0.05. Click here to view page 2 of the table of critical values of the F-distribution, for alpha = 0.05. The confidence interval is < (Round to three decimal places as needed.)
The number of unhealthy days based on the AQI (air quality index) for a random sample of metropolitan areas is shown. Construct an 80% confidence interval based on the data. Assume the variable is normally distributed. 23, 21, 14, 5, 40, 61, 39, 1, 0, 16

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