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Use a system of equations to find the quadratic function f(x) = ax2 + bx + c that satisfies the equations. Solve the system using matrices. f(1) = -2, f(2) = -3, f(3) = -6

Use a system of equations to find the quadratic function f(x) = ax2 + bx + c that satisfies the equations. Solve the system using matrices. f(1) = -2, f(2) = -3, f(3) = -6

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Use a system of equations to find the quadratic function f(x) = ax2 + bx + c that satisfies the equations. Solve the system using matrices. f(1) = -2, f(2) = -3, f(3) = -6
Transcribed Image Text:Use a system of equations to find the quadratic function f(x) = ax2 + bx + c that satisfies the equations. Solve the system using matrices. f(1) = -2, f(2) = -3, f(3) = -6
Step 1 The given quadratic function is f(x) = ax2 + bx + c. It is given that f(1) = -2, f(2) = -3, and f(3) = -6. Substitute x = 1, x = 2, and x = 3 into f(x) = ax2 + bx + c to form the system of linear equations. f(1) = a + b + c = -2 f(2) = 4a + 2b +c = -3 f(3) = 9a + 3b + c = -6 a + b + C = -2 Therefore, the obtained system of equations is {4a + 2b + c = -3. 9a + 3b + C = -6 Write the associated augmented matrix for this system. '1 1 1 : -2 4 2 1: -3 9 3 1: -6 To obtain the matrix in reduced row-echelon form, apply elementary row operations until every column that has a leading 1 has zeros in every position above and below its leading 1. Perform the operations (R2 - 4R1) on R2 and (R3 – 9R1) on R3. 1 -2 -2 -3 R2 - 4R1 → R3 - 9R1 0 -6 -8 ... ..
Transcribed Image Text:Step 1 The given quadratic function is f(x) = ax2 + bx + c. It is given that f(1) = -2, f(2) = -3, and f(3) = -6. Substitute x = 1, x = 2, and x = 3 into f(x) = ax2 + bx + c to form the system of linear equations. f(1) = a + b + c = -2 f(2) = 4a + 2b +c = -3 f(3) = 9a + 3b + c = -6 a + b + C = -2 Therefore, the obtained system of equations is {4a + 2b + c = -3. 9a + 3b + C = -6 Write the associated augmented matrix for this system. '1 1 1 : -2 4 2 1: -3 9 3 1: -6 To obtain the matrix in reduced row-echelon form, apply elementary row operations until every column that has a leading 1 has zeros in every position above and below its leading 1. Perform the operations (R2 - 4R1) on R2 and (R3 – 9R1) on R3. 1 -2 -2 -3 R2 - 4R1 → R3 - 9R1 0 -6 -8 ... ..
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