Use a sketch of the phase line to argue that any solution to the logistic model below, where a, b, and po are positive constants, approaches the equilibrium solution p(t) = as t approaches +∞. a dp dt =(a-bp)p: P(to) - Po First, define the phase line. The phase line for a differential equation The line describes the nature of the equilibrium solutions for f(y) indicates with dots and arrows the of the function dt
Use a sketch of the phase line to argue that any solution to the logistic model below, where a, b, and po are positive constants, approaches the equilibrium solution p(t) = as t approaches +∞. a dp dt =(a-bp)p: P(to) - Po First, define the phase line. The phase line for a differential equation The line describes the nature of the equilibrium solutions for f(y) indicates with dots and arrows the of the function dt
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Transcribed Image Text:Use a sketch of the phase line to argue that any solution to the logistic model below, where a, b, and po are positive constants, approaches the equilibrium
solution p(t)=ast approaches + ∞o.
dp
dt
=
a
(a - bp)p: p(to) = Po
dy
First, define the phase line. The phase line for a differential equation
= f(y) indicates with dots and arrows the
dt
of the function
The line describes the nature of the equilibrium solutions for
Sketch the phase line for
(a bp)p: p (to) Po Choose the correct sketch below.
A.
P
0
О в.
p=0
О с.
○ D.
a
p=0
10
a
p=0
a
towards p=
and for values of Po such that po
> the solution
b
a
How does the phase line indicate that any solution to the logistic model approaches the equilibrium solution p(t) = as t approaches +∞?
p=0.
a
The phase line shows that for values of po such that 0 <po <-
the solution
towards p=
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