Use a normal approximation to find the probability of the indicated number of voters. In this case, assume that 163 eligible voters aged 18-24 are randomly selected. Suppose a previous study showed that among eligible voters aged 18-24, 22% of them voted. Probability that fewer than 42 voted The probability that fewer than 42 of 163 eligible voters voted is (Round to four decimal places as needed.)

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**Finding the Probability Using Normal Approximation**

To find the probability of the indicated number of voters, we will use a normal approximation. In this case, assume that 163 eligible voters aged 18-24 are randomly selected. Suppose a previous study showed that among eligible voters aged 18-24, 22% of them voted.

**Problem Statement:**
Find the probability that fewer than 42 voters voted.

**Given Data:**
- Total eligible voters (n): 163
- Proportion of voters (p): 22% (or 0.22)

**Required Probability:**
The probability that fewer than 42 of 163 eligible voters voted.

**Solution Outline:**
1. Calculate the mean (μ) and standard deviation (σ) of the binomial distribution.
   
   Formula for mean (μ): 
   \[
   \mu = np
   \]

   Formula for standard deviation (σ): 
   \[
   \sigma = \sqrt{np(1-p)}
   \]
   
2. Convert the binomial probability to a normal probability by using the normal approximation to the binomial distribution.

3. Find the z-score for 42 voters.

4. Use the z-score to find the corresponding probability from the standard normal distribution table.

**Note:**
- Remember to round your final answer to four decimal places as needed.

---

**Note to the students:**
This example illustrates how to use the normal approximation to compute probabilities for a binomial distribution, especially when dealing with large sample sizes.

For further explanation and detailed step-by-step solutions, refer to the section on "Normal Approximation to the Binomial Distribution" in your statistics textbook.

(End of transcription)
Transcribed Image Text:**Finding the Probability Using Normal Approximation** To find the probability of the indicated number of voters, we will use a normal approximation. In this case, assume that 163 eligible voters aged 18-24 are randomly selected. Suppose a previous study showed that among eligible voters aged 18-24, 22% of them voted. **Problem Statement:** Find the probability that fewer than 42 voters voted. **Given Data:** - Total eligible voters (n): 163 - Proportion of voters (p): 22% (or 0.22) **Required Probability:** The probability that fewer than 42 of 163 eligible voters voted. **Solution Outline:** 1. Calculate the mean (μ) and standard deviation (σ) of the binomial distribution. Formula for mean (μ): \[ \mu = np \] Formula for standard deviation (σ): \[ \sigma = \sqrt{np(1-p)} \] 2. Convert the binomial probability to a normal probability by using the normal approximation to the binomial distribution. 3. Find the z-score for 42 voters. 4. Use the z-score to find the corresponding probability from the standard normal distribution table. **Note:** - Remember to round your final answer to four decimal places as needed. --- **Note to the students:** This example illustrates how to use the normal approximation to compute probabilities for a binomial distribution, especially when dealing with large sample sizes. For further explanation and detailed step-by-step solutions, refer to the section on "Normal Approximation to the Binomial Distribution" in your statistics textbook. (End of transcription)
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