Use a convergence test of your choice to determine whether the following series converges or diverges. M8 4 8 k=1 5k +5 Select the correct choice below and, if necessary, fill in the answer box to complete your choice. OE. OA. The Ratio Test yields r = This is greater than 1, so the series diverges by the Ratio Test. OB. The terms of the series are alternating and their limit is so the series converges by the Alternating Series Test. OC. The Ratio Test yields r= This is less than 1, so the series converges by the Ratio Test. O D. Because Because 4 5k +5 kº 4 8 5k +5 4 S and Σ 8 Z + .8 M8 M8 and k=1 k=1 4 ... 8 8 converges, the given series converges by the Comparison Test. diverges, the given series diverges by the Comparison Test.
Use a convergence test of your choice to determine whether the following series converges or diverges. M8 4 8 k=1 5k +5 Select the correct choice below and, if necessary, fill in the answer box to complete your choice. OE. OA. The Ratio Test yields r = This is greater than 1, so the series diverges by the Ratio Test. OB. The terms of the series are alternating and their limit is so the series converges by the Alternating Series Test. OC. The Ratio Test yields r= This is less than 1, so the series converges by the Ratio Test. O D. Because Because 4 5k +5 kº 4 8 5k +5 4 S and Σ 8 Z + .8 M8 M8 and k=1 k=1 4 ... 8 8 converges, the given series converges by the Comparison Test. diverges, the given series diverges by the Comparison Test.
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Transcribed Image Text:Use a convergence test of your choice to determine whether the following series converges or diverges.
M8
4
8
k=1 5k +5
Select the correct choice below and, if necessary, fill in the answer box to complete your choice.
OE.
OA. The Ratio Test yields r =
This is greater than 1, so the series diverges by the Ratio Test.
OB. The terms of the series are alternating and their limit is so the series converges by the Alternating Series Test.
OC. The Ratio Test yields r=
This is less than 1, so the series converges by the Ratio Test.
O D.
Because
Because
4
S
8
5k +5 kᵒ
4
8
5k +5
4
Z
+
.8
and Σ
M8 M8
and
k=1
k=1
4
...
8
8
converges, the given series converges by the Comparison Test.
diverges, the given series diverges by the Comparison Test.
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