Use a calculator to find the approximate value of the following expression if possible. Express your answers in radians and round to the hundredths. sin ¹ (2.12) 7.01 radians 5.01 radians Impossible since the value is not in the domain of sin¹ (x). 0.12 radians

Calculus: Early Transcendentals
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Author:James Stewart
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Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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**Finding the Approximate Value of the Inverse Sine Function**

**Problem Statement:**

Use a calculator to find the approximate value of the following expression if possible. Express your answers in radians and round to the hundredths.

\[ \sin^{-1}(2.12) \]

**Options:**

- A) 7.01 radians
- B) 5.01 radians
- C) Impossible since the value is not in the domain of \( \sin^{-1}(x) \)
- D) 0.12 radians

---

**Explanation:**

To solve this problem, it is important to recognize the domain of the inverse sine function, \( \sin^{-1}(x) \). The domain of \( \sin^{-1}(x) \) is \([-1, 1]\). This means that \( \sin^{-1}(x) \) is only defined for values of \( x \) within this interval.

Given the value 2.12, we note that this value is outside the domain of \( \sin^{-1}(x) \).

Therefore, the correct answer is:
- C) Impossible since the value is not in the domain of \( \sin^{-1}(x) \)
Transcribed Image Text:**Finding the Approximate Value of the Inverse Sine Function** **Problem Statement:** Use a calculator to find the approximate value of the following expression if possible. Express your answers in radians and round to the hundredths. \[ \sin^{-1}(2.12) \] **Options:** - A) 7.01 radians - B) 5.01 radians - C) Impossible since the value is not in the domain of \( \sin^{-1}(x) \) - D) 0.12 radians --- **Explanation:** To solve this problem, it is important to recognize the domain of the inverse sine function, \( \sin^{-1}(x) \). The domain of \( \sin^{-1}(x) \) is \([-1, 1]\). This means that \( \sin^{-1}(x) \) is only defined for values of \( x \) within this interval. Given the value 2.12, we note that this value is outside the domain of \( \sin^{-1}(x) \). Therefore, the correct answer is: - C) Impossible since the value is not in the domain of \( \sin^{-1}(x) \)
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