Use (a) bisection method and (b) false position method to find the solution to the following within error of 10-6. Show your manual solution for first three iterations, then prepare an Excel file for the finding the root until the error is within 10-6 showing also the graph of the function. 1. x³-2x²-5=0, when x = [1, 4]
Use (a) bisection method and (b) false position method to find the solution to the following within error of 10-6. Show your manual solution for first three iterations, then prepare an Excel file for the finding the root until the error is within 10-6 showing also the graph of the function. 1. x³-2x²-5=0, when x = [1, 4]
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter2: Equations And Inequalities
Section2.3: Quadratic Equations
Problem 81E
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![Use (a) bisection method and (b) false position method to find the solution to the following within error of 10-6. Show your manual solution
for first three iterations, then prepare an Excel file for the finding the root until the error is within 10-6 showing also the graph of the
function.
1. x3-2x2-5=0, when x = [1, 4]
2. sin x - eX=0, when x =
[0,1]
3. (x-2)2-In x =0, when x = [1,2]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff5a12e07-8b4d-4108-bcd0-642e19766f05%2F84b7633c-e61e-4f79-9a23-201196ed4147%2F0pqubk_processed.png&w=3840&q=75)
Transcribed Image Text:Use (a) bisection method and (b) false position method to find the solution to the following within error of 10-6. Show your manual solution
for first three iterations, then prepare an Excel file for the finding the root until the error is within 10-6 showing also the graph of the
function.
1. x3-2x2-5=0, when x = [1, 4]
2. sin x - eX=0, when x =
[0,1]
3. (x-2)2-In x =0, when x = [1,2]
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