10Benford's Law states that the first nonzero digits of numbers drawn at random from a large complex datafile have the following probability distribution.tFirstNonzeroDigitProbabili10.30120.176First Nonzero Digit 1Sample FrequencyUSE SALT30.1252 380 55 33State the null and alternate hypotheses.Ho: The distributions are different.H: The distributions are different.H: The distributions are the same.H: The distributions are different.H₁: The distributions are the same.0.0974Are all the expected frequencies greater than 5?Yes NoWhat sampling distribution will you use?uniform binomialWhat are the degrees of freedom?422normal chi-square50.079tySuppose that n = 275 numerical entries were drawn at random from a large accounting file of a majorcorporation. The first nonzero digits were recorded for the sample.60.067Ho: The distributions are the same.Ho: The distributions are the same.Ho: The distributions are different.(c) Estimate the P-value of the sample test statistic.P-value > 0.100 0.050 < P-value < 0.1000.005< P-value < 0.010 P-value < 0.0055621 18713Use a 1% level of significance to test the claim that the distribution of first nonzero digits in thisaccounting file follows Benford's Law.(a) What is the level of significance?Student's t70.05888170.051(b) Find the value of the chi-square statistic for the sample. (Round the expected frequencies to at leastthree decimal places. Round the test statistic to three decimal places.)91690.046(d) Based on your answers in parts (a) to (c), will you reject or fail to reject the null hypothesis ofindependence?0.025 < P-value < 0.050 0.010 < P-value < 0.025Since the P-value > a, we fail to reject the null hypothesis. Since the P-value > a, we reject the nullhypothesis.Since the P-value s xx, we reject the null hypothesis. Since the P-values a, we failto reject the null hypothesis.(e) Interpret your conclusion in the context of the application.At the 1% level of significance, the evidence is sufficient to conclude that the distribution of first nonzerodinite in the secounting file do not follow Danford'e LowAt the 10 laual of signifinonan the suidonea.

Given that sample size (n) = 275 Non-zero digit Sample frequency (O) Probability according to…

Answered: Use a 1% level of significance to test…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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. nonzerorands expects 3 arguments The average American consumes 100 liters of alcohol per year. Does the average college student consume a different amount of alcohol per year? A researcher surveyed 15 randomly selected college students and found that they averaged 86 liters of alcohol consumed per year with a standard deviation of 16 liters. What can be concluded at the the a = 0.05 level of significance? a. For this study, we should use t-test for a population mean b. The null and alternative hypotheses would be: Ho: μν H₁: 100 100 E -3.389 (please show your answer to 3 decimal places.) (Please show your answer to 4 decimal places.) c. The test statistic t d. The p-value = e. The p-value is > ✓ a f. Based on this, we should fail to reject g. Thus, the final conclusion is that ... the null hypothesis. O The data suggest the populaton mean is significantly different from 100 at a = 0.05, so there is statistically significant evidence to conclude that the population mean amount of…
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(d) Annual salaries of the employees at a Fortune 500 company where only a few high level executives earn much higher salaries than the all other employees. The distribution is expected to be: O left skewed O symmetric O right skewed A typical observation is best represented by the: O mean O median The variability in the observations is best measured by the: O IQR O standard deviation
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Q1. Which of these is not a parameter of the population distribution of X? A. Sample Mean of X. B. Variance of X. C. Std. deviation of X. D. The Expected value of X, E(X). O A. A В. Ь О С. с O D. d
How is the t distribution different from the Z distribution? a. The t distribution does not have any negative numbers. b. The t distribution is asymmetrical; that is, it is not a mirror image on each side of the population mean. c. The t distribution is wider than the Z distribution due to lower sample size. d. All of the above are differences between the t and Z distributions
State the null and alternate hypothesis. Will you use a left tail, right tail or 2 tailed test? Identify the sampling distribution to be used: standard normal, Student’s t or chi squared. Find the value of the test statistic. Find the P-Value. Based on your answers, shall we reject or accept the null hypothesis? Write the conclusion in the context of the problem.
3. Which one of the following statements is false? 1. A correlation of –0.70 is weaker than a correlation of +0.70. 2. As the sample size gets larger, the standard deviation of the sampling distribution will get smaller. 3. A sampling distribution is a collection of sample statistics 4. Chance behavior is predictable in the long run but has an unpredictable pattern in the short run. 5. The size of the sample proportion has an impact on the margin of error.
A weight-loss clinic advertised that last month its patients, on average, lost 6 lb. Assuming that average refers to the mean, which of the following claims must be true based on this information? Note: More than one statement could be true. If none of the statements is true, mark the appropriate box. Last month, the number of their clients who lost 6 lb or more was equal to the number of their clients who lost 6 lb or less. Last month at least one of their patients lost exactly 6 lb. Last month at least one of their patients lost less than 10 lb. Two months ago some of their patients lost at least 6 lb. Last month all of their patients lost 6 lb or more. None of the above statements are true. X Ś A 181 Aa ?
Q: Fewer than 90% of adults have a cell phone. This is a claim about a population proportion so a normal distribution is assumed. The claim undergoes a hypothesis test using a significance level of α = 0.05. The P-value based on sample data is calculated to be 0.0003. On your graph, next highlight the P-value. (The P-value means that there is a 0.03% chance that your results could be random or happen by chance). State a conclusion about the null hypothesis. (Reject H0 or fail to reject H0.) Without using technical terms or symbols, state a final conclusion that addresses the original claim, i.e., fewer than 90% of adults have a cell phone.Now we will test this hypothesis using the critical value method. The z statistic is most relevant to this test. Using the z-score tables at the back of the textbook, find the z-score for a significance level of α = 0.05. This is the critical value. What is it? Sketch a normal distribution curve, plot the critical value, and highlight the critical…
B. Explain the following: 1. What is a t-distribution? 2. When is a z-test and the t-test used?
I need help with parts 2,3, and 6

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