Use (20) in Section 6.4. 1 - 2a y" + + (b²c²x²c − 2 + 0² - p²c²)y ₁ X Find the general solution of the given differential equation on (0, ). (The definitions of various Bessel functions are given here.) xy" + 2y' + 9y = 0 ○ y(x) = x¹/² [C₁J₁ (3x −¹/2) + C₂Y₁(3x-¹/2)] Ⓒy(x) = x-¹/²[C₁³₁ (3x¹/2) + C₂Y₁(3x¹/2)] O y(x) = x-1/² [C₁J₁ (6x¹/2) + C₂Y₁(6x¹/2)] O y(x) = x-¹/² [C₁J₁ (3x¹/2) + C₂J_1(3x¹/2)] 1/2. -1/2. y = 0, p≥0 (20) -1/2..
Use (20) in Section 6.4. 1 - 2a y" + + (b²c²x²c − 2 + 0² - p²c²)y ₁ X Find the general solution of the given differential equation on (0, ). (The definitions of various Bessel functions are given here.) xy" + 2y' + 9y = 0 ○ y(x) = x¹/² [C₁J₁ (3x −¹/2) + C₂Y₁(3x-¹/2)] Ⓒy(x) = x-¹/²[C₁³₁ (3x¹/2) + C₂Y₁(3x¹/2)] O y(x) = x-1/² [C₁J₁ (6x¹/2) + C₂Y₁(6x¹/2)] O y(x) = x-¹/² [C₁J₁ (3x¹/2) + C₂J_1(3x¹/2)] 1/2. -1/2. y = 0, p≥0 (20) -1/2..
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Related questions
Question
![Use (20) in Section 6.4.
-
y" + 1 − 2ªy' + (6²c²x²c − 2 + a² − p²c²),
-
X
= 0, p≥ 0 (20)
Find the general solution of the given differential equation on (0, ∞). (The definitions of various Bessel functions are given here.)
xy" + 2y' + 9y = 0
O y(x) = x¹/²[C₁³₁(3x-¹/2) + C₂Y₁(3x-¹/2)]
Ⓒ y(x) = x¯¹/²[C₁J₁ (3x¹/2) + C₂Y₁(3x¹/2)]
O y(x) = x ¹/2[C₁J₁ (6x¹/2) + C₂Y₁(6x¹/2)]
○ y(x) = x-¹/²[C₁J₁ (3x¹/2) + C₂³_₁(3x¹/2)]
○ y(x) = x¹/²[C₁J₁(6x−1/2) + C₂Y₁(6x−¹/2)]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F278fbf48-8175-4c44-ac0e-2265809c567f%2F2e0bb957-15da-45aa-88dc-5b05be5e5582%2Fskezskx_processed.png&w=3840&q=75)
Transcribed Image Text:Use (20) in Section 6.4.
-
y" + 1 − 2ªy' + (6²c²x²c − 2 + a² − p²c²),
-
X
= 0, p≥ 0 (20)
Find the general solution of the given differential equation on (0, ∞). (The definitions of various Bessel functions are given here.)
xy" + 2y' + 9y = 0
O y(x) = x¹/²[C₁³₁(3x-¹/2) + C₂Y₁(3x-¹/2)]
Ⓒ y(x) = x¯¹/²[C₁J₁ (3x¹/2) + C₂Y₁(3x¹/2)]
O y(x) = x ¹/2[C₁J₁ (6x¹/2) + C₂Y₁(6x¹/2)]
○ y(x) = x-¹/²[C₁J₁ (3x¹/2) + C₂³_₁(3x¹/2)]
○ y(x) = x¹/²[C₁J₁(6x−1/2) + C₂Y₁(6x−¹/2)]
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