Hint(s) Check My WorkUSA Today reports that the average expenditure on Valentine's Day was expected to be $100.89. Do male and female consumers differ in the amounts they spend? Theaverage expenditure in a sample survey of 40 male consumers was $133.85, and the average expenditure in a sample survey of 36 female consumers was $64.27. Based onpast surveys, the standard deviation for male consumers is assumed to be $34, and the standard deviation for female consumers is assumed to be $18. The z value is 2.576Round your answers to 2 decimal places.a. What is the point estimate of the difference between the population mean expenditure for males and the population mean expenditure for females?b. At 99% confidence, what is the margin of error?c. Develop a 99% confidence interval for the difference between the two population means.to

The sample size for males is 40, mean is 133.85, population standard deviation is 34, and the sample…

Answered: USA Today reports that the average…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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USA Today reports that the average expenditure on Valentine's Day was expected to be $100.89. Do male and female consumers differ in the amounts they spend? The average expenditure in a sample survey of 54 male consumers was $132.57, and the average expenditure in a sample survey of 35 female consumers was $70. Based on past surveys, the standard deviation for male consumers is assumed to be $33, and the standard deviation for female consumers is assumed to be $16. The z value is 2.576. Round your answers to 2 decimal places. a. What is the point estimate of the difference between the population mean expenditure for males and the population mean expenditure for females? b. At 99% confidence, what is the margin of error? c. Develop a 99% confidence interval for the difference between the two population means. to
The mean monthly rent for a one-bedroom apartment without a doorman in Manhattan is $2663. Assume the standard deviation is $506. A real estate firm samples 106 apartments. Find the 9 percentile of the sample mean. Round the answer to at least two decimal places.
Is it worth pursuing a doctoral degree in education if you already have an undergraduate degree? One way to help make this decision is to look at the mean incomes of these two groups. Suppose that 15 people with bachelor’s degrees in education were surveyed. Their mean annual salary was $⁢31,500 with a standard deviation of $⁢7900. Seventeen people with doctoral degrees in education were found to have a mean annual salary of $⁢47,500 with a standard deviation of $⁢6900. Assume that the population variances are not the same. Construct a 99% confidence interval to estimate the true difference between the mean salaries for people with doctoral degrees and undergraduate degrees in education. Let Population 1 be the salaries for people with doctoral degrees and Population 2 be the salaries for people with undergraduate degrees. Round the endpoints of the interval to the nearest whole number, if necessary.
The manager of a major retail store has taken a random sample of 25 customers. The average sale was $52.50. The population standard deviation is known to be $6.10. The manager would like to determine whether or not the mean sales by all customers are significantly more than $50. What is the p-value for the test?
It is known that incomes from the USA follow a normal distribution with a mean of $55,000 and a standard deviation of $12,000. A researcher took a sample of 100 people in the USA and obtained a sample mean of $67,000 with a standard deviation of $18,000. What are the characteristics of the sampling distribution. A. Mean = $55,000 and Standard Deviation of the Mean = $1200 B. Mean = $55,000 and Standard Deviation of the Mean = $12000 C. Mean = $67,000 and Standard Deviation of the Mean = $569.21 D. Mean = $67,000 and Standard Deviation of the Mean = $1800
Student loan debt is the only form of consumer debt that has grown since the peak of consumer debt in 2008. The average student loan of somebody younger than 30 is $24,350. Assume the standard deviation for debt is $3,000 per student.
the mean charge for satellite television for a sample of households was $87.50 per month, with a standard deviation of $14.50 per month. Estimate the percent of satellite television charges between $73.00 and $102.00
The providence health maintenance organization wants to establish a criterion for recommending dietary changes if cholesterol levels are in the top 3%. What is the cutoff level for men aged 18 to 24 and the mean is 178.1 and the standard deviation is 40.7
The average expenditure on Valentine's Day was expected to be $100.89 (USA Today, February 13, 2006). Do male and female consumers differ in the amounts they spend? The average expenditure in a sample survey of 46 male consumers was $132.31, and the average expenditure in a sample survey of 37 female consumers was $63.58. Based on past surveys, the standard deviation for male consumers is assumed to be $33, and the standard deviation for female consumers is assumed to be $20. The z value is 2.576. Round your answers to 2 decimal places. a. What is the point estimate of the difference between the population mean expenditure for males and the population mean expenditure for females? b. At 99% confidence, what is the margin of error? c. Develop a 99% confidence interval for the difference between the two population means. to
According to one study, the average hours of sleep on a weeknight for men was 6.9 hours with a standard deviation of 1.5 hours. These hours are normally distributed. c. Find the proportion of men who sleep between 6-8 hours per night. d. Find the number of hours that represents the 90th percentile.
The USA Today reports that the average expenditure on Valentine's Day is $100.89. Do male and female consumers differ in the amounts they spend? The average expenditure in a sample survey of 45 male consumers was $135.67, and the average expenditure in a sample survey of 32 female consumers was $68.64. Based on past surveys, the standard deviation for male consumers is assumed to be $34, and the standard deviation for female consumers is assumed to be $20. What is the point estimate of the difference between the population mean expenditure for males and the population mean expenditure for females (to 2 decimals)? At 99% confidence, what is the margin of error (to 2 decimals)? Develop a 99% confidence interval for the difference between the two population means (to 2 decimals). Use z-table.( , )

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