USA Today reports that the average expenditure on Valentine's Daywas expected to be $100.89. Do male and female consumers differin the amounts they spend? The average expenditure in a samplesurvey of 40 male consumers was $135.67, and the averageexpenditure in a sample survey of 30 female consumers was $68.64.. Based on past surveys, the standard deviation for male consumersis assumed to be $35, and the standard deviation for femaleconsumers is assumed to be $20. The z value is 2.576.Round your answers to 2 decimal places.a. What is the point estimate of the difference between thepopulation mean expenditure for males and the population meanexpenditure for females?6703b. At 99% confidence, what is the margin of error?16.33c. Develop a 99% confidence interval for the difference between thetwo population means.to 83.36 *50.70

The average expenditure in a sample of 40 male consumers was $135.67 with the population standard…

Answered: USA Today reports that the average…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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USA Today reports that the average expenditure on Valentine's Day was expected to be $100.89. Do male and female consumers differ in the amounts they spend? The average expenditure in a sample survey of 54 male consumers was $132.57, and the average expenditure in a sample survey of 35 female consumers was $70. Based on past surveys, the standard deviation for male consumers is assumed to be $33, and the standard deviation for female consumers is assumed to be $16. The z value is 2.576. Round your answers to 2 decimal places. a. What is the point estimate of the difference between the population mean expenditure for males and the population mean expenditure for females? b. At 99% confidence, what is the margin of error? c. Develop a 99% confidence interval for the difference between the two population means. to
Is a measure of 29 inches "far away" from a mean of 19 inches? Suppose the data come from a sample whose standard deviation is 2 inches. A. How many standard deviation is 29 inches from 19 inches? b. Is 29 inches far away from a mean of 19 inches? c. Suppose the standard deviation of the underlying data is 7 inches. Is 29 inches far away from a mean of 19 inches?
Student loan debt is the only form of consumer debt that has grown since the peak of consumer debt in 2008. The average student loan of somebody younger than 30 is $24,350. Assume the standard deviation for debt is $3,000 per student.
According to a government study among adults in the 25 to 34-year age group, the mean amount spent per year on reading and entertainment is $1,994. Assume that the distribution of the amounts spent follows the normal distribution with a standard deviation of $350. a. What percent of the adults spend more than $2,500 per year on reading and entertainment? b. What percent spend between $2,500 and $2,800 per year on reading and entertainment?
Mario's weekly poker winnings have a mean of $353 and a standard deviation of $67. Last week he won $185. How many standard deviations from the mean is that?
The providence health maintenance organization wants to establish a criterion for recommending dietary changes if cholesterol levels are in the top 3%. What is the cutoff level for men aged 18 to 24 and the mean is 178.1 and the standard deviation is 40.7
The average expenditure on Valentine's Day was expected to be $100.89 (USA Today, February 13, 2006). Do male and female consumers differ in the amounts they spend? The average expenditure in a sample survey of 46 male consumers was $132.31, and the average expenditure in a sample survey of 37 female consumers was $63.58. Based on past surveys, the standard deviation for male consumers is assumed to be $33, and the standard deviation for female consumers is assumed to be $20. The z value is 2.576. Round your answers to 2 decimal places. a. What is the point estimate of the difference between the population mean expenditure for males and the population mean expenditure for females? b. At 99% confidence, what is the margin of error? c. Develop a 99% confidence interval for the difference between the two population means. to
A successful basketball player has a height of 6 feet 11 inches, or 211 cm. Based on statistics from a data set, his height converts to the z score of 5.17. How many standard deviations is his height above the mean?
What does a mean of 9.1429 and a standard deviation of 2.5455 tell you
Approximately 10% of people in the U.S. earn an income of $200,000 per year or higher. If income were normally distributed, and the mean income is $40,000 per year, what is the standard deviation of income in the U.S.? (Note. these figures are not accurate.)
The USA Today reports that the average expenditure on Valentine's Day is $100.89. Do male and female consumers differ in the amounts they spend? The average expenditure in a sample survey of 45 male consumers was $135.67, and the average expenditure in a sample survey of 32 female consumers was $68.64. Based on past surveys, the standard deviation for male consumers is assumed to be $34, and the standard deviation for female consumers is assumed to be $20. What is the point estimate of the difference between the population mean expenditure for males and the population mean expenditure for females (to 2 decimals)? At 99% confidence, what is the margin of error (to 2 decimals)? Develop a 99% confidence interval for the difference between the two population means (to 2 decimals). Use z-table.( , )

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