Urn A contains 6 white balls and 9 black balls. Urn B contains 6 white balls and 8 black balls. First, one ball is drawn at random from Urn A and placed in Urn B. A ball is then drawn at random from Urn B and put in Urn A. At the conclusion of this process, what is the probability that Urn A still contains 6 white balls and 9 black balls?

A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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Urn A contains 6 white balls and 9 black balls. Urn B contains 6 white balls and 8 black balls. First, one ball is drawn at random from Urn A and placed in Urn B. A ball is then drawn at random from Urn B and put in Urn A. At the conclusion of this process, what is the probability that Urn A still contains 6 white balls and 9 black balls?

Expert Solution
Step 1

In urn A :

Number of white balls is 6 .

Number of black balls is 9 .

In urn B :

Number of white balls is 6 .

Number of black balls is 8 .

First, one ball is drawn at random from Urn A and placed in Urn B. A ball is then drawn at random from Urn B and put in Urn A .

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