Update the provided code to a code that uses while loop and then simulate.
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Update the provided code to a code that uses while loop and then simulate.
const int PinLed = 13;
const int time = 500;
void setup() {
pinMode(PinLed, OUTPUT);
}
void loop() {
for(int i = 0; i <= 4; i++){
digitalWrite(PinLed, HIGH);
delay(time); // Wait for Time in millisecond(s)
digitalWrite(PinLed, LOW);
delay(time);// Wait for Time in millisecond(s)
}
delay(10000); // 10 second
}
Step by step
Solved in 2 steps
- int LED void setup () { pinMode (LED,OUTPUT) ; void loop 0 digitalWrite (LED,HIGH); delay (1000) ; digitalWrite (LED, LOW) ; delay (1000); For the following circuit board, the following code was applied to make the LED blink every one second. 1- If the LED was connected to pin 5 and the delay was 3 seconds. Modify the code to accommodate these changes. 2- How does the LED blinking changes between the two codes? DIGITAL (PWM 0O UNO ARDUINO ANALOG 222222Explain the function of the given code: int timer = 100; int ledPins[] = { 2, 7, 4, 6, 5, 3 }; int pinCount = 6; void setup() { for (int thisPin = 0; thisPin = thisPin--) { digitalWrite(ledPins[thisPin], HIGH); delay(timer); digitalWrite(ledPins[thisPin], LOW); } 0;SPIM simulator (QtSpim). Simulation: Write a MIPS program that computes the expression; y = A * B + C * D Where A, B, C, and D are integers
- Run the programme and identify the outputs: void Test (int z[]) #include using namespace std; void Test (int []); int main () { int myArr [4]={3,4,5,6}; { int temp=z[3] ; z[3]=z[0]; z [0]=temp; for (int i=0;i<4;i++) cout<Explain the following code? const int analogPin = A0; const int ledCount = 10; int ledPins[] = { 2, 3, 4, 5, 6, 7, 8, 9, 10, 11 }; void setup() { for (int thisLed = 0; thisLed < ledCount; thisLed++) { pinMode(ledPins[thisLed], OUTPUT); } } void loop() { int sensorReading = analogRead(analogPin); // map the result to a range from 0 to the number of LEDs: int ledLevel = map(sensorReading, 0, 1023, 0, ledCount); for (int thisLed = 0; thisLeddef apply_gaussian_noise(X, sigma=0.1): """ adds noise from standard normal distribution with standard deviation sigma :param X: image tensor of shape [batch, 3, height, width] Returns X + noise. """ ### YOUR CODE HERE ### # noise tests theoretical_std = (X_train[:100].std() ** 2 + 0.5 ** 2) ** .5 our_std = apply_gaussian_noise(X_train[:100], sigma=0.5).std() assert abs(theoretical_std - our_std) < 0.01, \ "Standard deviation does not match it's required value. Make sure you use sigma as std." assert abs(apply_gaussian_noise(X_train[:100], sigma=0.5).mean() - X_train[:100].mean()) < 0.01, \ "Mean has changed. Please add zero-mean noise"Consider the following code: int sum = 0; int i = 0; while (i < 6) { sum = sum + i; i++;} Convert while loop to for loop a. for (int i = 1; i < 7; i++) sum = sum + i; b. for (int i = 0; i <= 6; i++) sum = sum + i; c. for (int i = 1; i <= 6; i++) sum = sum + i; d. for (int i = 0; i < 6; i++) sum = sum + i; e. for (int i = 2; i < 6; i++) sum = sum + i;using System; class HelloWorld { static void Main() { int rows=21; int columns=76; for(int i=0;i<rows;i++) //for loop for printing the pattern for 21 rows { for(int j=1;j<=columns;j++) //for loop for printing the pattern in 76 columns { if((i+j)%7!=1 ) //if the addition of i and j does not give remainder of 1 when divided by 7 then Console.Write("-"); //print dash - on console else //otherwise peint a space on console Console.Write(" "); } Console.WriteLine(); //print a newline for printing on new row... } } }public void TestValues( int a, int b, ref int x ) { if (a > 0) && (b > 0) x = 1; if (a < 0) && (b < 0) x = -1; } Generate test cases for the code based on MC/DC coverage criteriaWith the help of a program in C language find the number of iterations of the loop given below: for (int i=100; i>0; i=i/2){ for(int j=1; j<=100; j=j*2){ |/constant time work } }JAVA: Replace the for loop below with a code using the "While" loop: int s = 0; int c = 0; boolean valid = true; for(int i = 4; i <= 20 || valid; i = i+2) { if(i%4 != 0) { s = s + i; c++; } if(i > 20) { valid = false; } } System.out.println(s / c);for (int i = 1; i <= 3; i++) { for (int j = 1; j <= 3; j++) { System.out.print((i * j) + " "); }SEE MORE QUESTIONSRecommended textbooks for youDatabase System ConceptsComputer ScienceISBN:9780078022159Author:Abraham Silberschatz Professor, Henry F. Korth, S. SudarshanPublisher:McGraw-Hill Education
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