**Problem 34.27**Unpolarized light with intensity \(310 \, \text{W/m}^2\) passes first through a polarizing filter with its axis vertical, then through a second polarizing filter. It emerges from the second filter with intensity \(127 \, \text{W/m}^2\).---**Part A**What is the angle from vertical of the axis of the second polarizing filter?**Express your answer to two significant figures and include the appropriate units.**\[\theta = \text{Value} \quad \text{Units}\][Submit] [My Answers] [Give Up]---*Explanation:*The problem involves calculating the angle of the second polarizer relative to the vertical axis, using the initial and final intensities of light after passing through two polarizers. Use Malus's law in your calculations, which relates the transmitted light intensity to the angle between the light's polarization direction and the polarizer's axis.

Malu's law states that the intensity of the plane-polarized light that passes through the analyzer…

Answered: Unpolarized light with intensity 310…

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