Suppose that the creatine kinase levels among healthy males are normally distributed with a standard deviation of 22unitsResearch shows that exactly 5% ofunits. What is the mean creatine kinase level in healthy males? Carry your intermediate computationsthe healthy males have a creatine kinase level above 150to at least four decimal places. Round your answer to at least one decimal place.units

Answered: Image /qna-images/answer/22ce445d-6579-4b5d-a955-640ac00a755b.jpg

Answered: units . Research shows that exactly 5%…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Assume that a randomly selected subject is given a bone density test. Bone density test scores are normally distributed with a mean of 0 and a standard deviation of 1. Draw a graph and find P9, the 9th percentile. This is the bone density score separating the bottom 9% from the top 91%. Which graph represents P9? Choose the correct graph below.
Assume that a randomly selected subject is given a bone density test. Bone density test scores are normally distributed with a mean of 0 and a standard deviation of 1. Draw a graph and find P, the 11th percentile. This is the bone density score separating the bottom 11% from the top 89%. Which graph represents P ? Choose the correct graph below. O A. O B. OD. P11 P11 P11 P11 The bone density score corresponding to P1 is (Round to two decimal places as needed.) Click to select your answer(s). APR tv MacBook Air F9 F10 LLA 20 F3 F6 F8 F4 F5 F1 F2 & #3 7 8. %24
Use the formula to find the standard error of the distribution of differences in sample means, ₁ - ₂. Samples of size 35 from Population 1 with mean 3.1 and standard deviation 1.8 and samples of size 35 from Population 2 with mean 2.0 and standard deviation 1.4 Round your answer for the standard error to two decimal places. standard error = i
IQ Scores. In Exercises,find the area of the shaded region. The graphs depict IQ scores of adults, and those scores are normally distributed with a mean of 100 and a standard deviation of 15 (as on the Wechsler test).
Calcium levels in people are normally distributed with a mean of 9.7 mgdL and a standard deviation of 0.5 mgdL . Individuals with calcium levels in the bottom 10% of the population are considered to have low calcium levels. Find the calcium level that is the borderline between low calcium levels and those not considered low. Carry your intermediate computations to at least four decimal places. Round your answer to one decimal place.
21 d-f
1:15 (a) Which variable is the explanatory variable? OA. One of the biggest factors in determining the value of a home is the square footage. The accompanying data represent the square footage and selling price (in thousands of dollars) for a random sample of homes for sale in a certain region. Complete parts (a) through (h) below. Click the icon to view the housing data. Square Footage Selling Price (b) Draw a scatter diagram of the data. Choose the correct scatter diagram below. Ay 4500- 000 1000 mylab.pearson.com/ + ® : 3 4500 Data Table Q Square Footage, x 2148 3231 1177 1988 3064 2735 4146 2215 2625 1629 1773 3887 Print ||| OB. r= 0.899 (Round to three decimal places as needed.) = AX 4500- 1000+++ 150 750 Q (c) Determine the linear correlation coefficient between square footage and asking price. Done Ay 750- Vo) 1 LTE2 150- O 1000 Selling Price ($000s), y D 371.1 382.2 197.6 339.9 614.9 364.7 632.7 377.7 427.5 285.9 268.9 701.4 4500 .... .... Q X D. Ay 750- 41% 150+ 1000 4500
Assume that a randomly selected subject is given a bone density test. Bone density test scores are normally distributed with a mean of 0 and a standard deviation of 1. Draw a graph and find Upper P 10 ,the 10 th percentile. This is the bone density score separating the bottom 10% from the top 90%. a. The bone density score corresponding to Upper P 10 is (Round to two decimal places as needed.)
Student 3 300 mm 1000 mm 1400 mm 1000 mm 1600 mm 1800 mm 2000 mm Average distance for student 3 = Error for student 3= Standard deviation for student 3= Uncertainty for student 3=
The average amount of money spent by an Amazon customer per month is $1296 with standard deviation $110. Assume the variable is normally distributed. Answer the following questions. What is the probability that a random sample of 15 Amazon customers spent an average between $1100 and $1300 in a month?
%23 34.152 is an approx number. The no. is correct up to five significant digits Find the upper Limit for Ihe relative error.
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