unit normal to the surface (x3)² = 4[(x₁)² + (x₂)²] at A. (2/3)î₁ - (1/3)î₂ + (2/3)13 B. (1/√6) + (1/√6)₁₂ - (2/√6)13 E. (2/3)1₁ +(2/3)^₂ - (1/3)13 C. D. (1,1,2) (1/3)î₁ + (2/3)^₂ + (2/3)13 (1/√6)î₁ + (1/√6)î₂ + (2/√6)î
unit normal to the surface (x3)² = 4[(x₁)² + (x₂)²] at A. (2/3)î₁ - (1/3)î₂ + (2/3)13 B. (1/√6) + (1/√6)₁₂ - (2/√6)13 E. (2/3)1₁ +(2/3)^₂ - (1/3)13 C. D. (1,1,2) (1/3)î₁ + (2/3)^₂ + (2/3)13 (1/√6)î₁ + (1/√6)î₂ + (2/√6)î
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
Related questions
Question
![unit normal to the surface (x3)² = 4[(x₁)² + (x₂)²] at
A.
(2/3)î₁ - (1/3)î₂ + (2/3)î3
C.
D.
B. (1/√6)₁₁ + (1/√6)î2 − (2/√6)î3
E. (2/3)î₁ +(2/3)î₂ – (1/3)î3
(1,1,2)
−(1/3)î₁ + (2/3)î₂ + (2/3)13
(1/√6)î₁ + (1/√6)î2 + (2/√6)î3](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F579b1e72-f803-4bbd-82dc-3b303280eeca%2Fd7a96326-c2a1-4c7a-bbfe-b94ed572d80d%2F4alh3as_processed.png&w=3840&q=75)
Transcribed Image Text:unit normal to the surface (x3)² = 4[(x₁)² + (x₂)²] at
A.
(2/3)î₁ - (1/3)î₂ + (2/3)î3
C.
D.
B. (1/√6)₁₁ + (1/√6)î2 − (2/√6)î3
E. (2/3)î₁ +(2/3)î₂ – (1/3)î3
(1,1,2)
−(1/3)î₁ + (2/3)î₂ + (2/3)13
(1/√6)î₁ + (1/√6)î2 + (2/√6)î3
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