The answer is e. Why does the else statement override the first if statement, which is true. Please explain why e, and only e is correct with no process of elimination Safari File Edit(ВUnit 3 Progress Check: MCQⒸDlow = c;}View}if (a > b && c> b){low = b;}else(Orderslow = a;Historya = 1, b = 1, c = 2a = 1, b = 2, c = 1a = 1, b = 2, c = 3a = 2, b = 2, c = 2Collega = 3, b = 2, c = 1Bookmarks Window HelpDrive..Ⓒ 010System.out.println(a + b + c - low);For which of the following values of a, b, and c does the code segment NOT print the correct value?A11Univer....1213)NYU E14 (15)Assume that the int variables a, b, c, and low have been properly declared and initialized. The code segment below is intended to print the sum of the greatest two of the three values but does not work in some cases.if (a > b && b > c){16)Assignapclassroom.collegeboard.orgOlivia...18) 192021SandbNew SOSalmoCSNew S

Solution for the above question, This is simple Java code by using if and if else statements. Solution: (a>b&&b>c) { low=c; } if(a>b&&c>b) { low=b; } else { low=a; } system.out.println(a+b+c-low) Explanation: It have to print sum of the greatest two of the three values means, to understand, if a>b>c means , it have to print a+b if b>a>c means it have to print b+a if c>a>b means it have to print c+a so we have to find the greatest two of a,b,c, it may be a,b or c,a, c,b. Let see the coding: when the first if condition is true , it has to assign low=c (which means greater values are a,b, so sum of the greatest two of three values is a+b) if(a>b&&b>c) { low=c; } (a+b+c-low) ( take values in option e) if (3>2and 2>1) condition true, so low=1 (c), as per our guess sum of greatest two is (3+2=5), as per code (3+2+1-1=5) so it will print the correct value. But in given coding there is also another if statement , so when the first if statement is correct , it will move to second if statement then there the condition if(a>b&&c>b) will be false and it will take to else part , there is another value for low to assing in else statement, if it happens low will be assigned as a(low=a), but it is not right low should be c. There should not be another if statement after the first statement, becuase in this code, whether the tirst if statement is true or false it has to go through the second if statement.Flow chart of the program is The program structure is designed like there is no direct path to output statement from first if statement , the first if statement should cross the second if whethere it si true or false, so it cannot print correct value , when we select option e.Option A: a=1,b-1,c=2 option B: a=1,b=2,c=1 option C: a=1,b=2, c=3 option D: a=2,b=2,c=2 when we check option A to D , the first condition will be false, there is not value to assign in low here, then it will go to second if statement. Here the second if condion also false to all option A to D, so the control moves to else part, it assign low value as a (low=a), it will print result as ((a+b+c)-a) so for option A: (1+1+2-1)=3, option B: (1+2+1-1)=3, option C: (1+2+3-1)=5, option D: (2+2+2-1)=5.