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Under the action of force P, the constant acceleration of block B is 7.9 ft/sec? up the incline. For the instant when the velocity of B is 2.0 ft/sec up the incline, determine the velocity of B relative to A (positive if up the slope, negative if down), the acceleration of B relative to A (positive if up the slope, negative if down), and the absolute velocity of point C (positive if up the slope, negative if down) of the cable. 24° Answers: VB/A = ft/sec ft/sec2 aB/A = Vc= ft/sec

Under the action of force P, the constant acceleration of block B is 7.9 ft/sec? up the incline. For the instant when the velocity of B is 2.0 ft/sec up the incline, determine the velocity of B relative to A (positive if up the slope, negative if down), the acceleration of B relative to A (positive if up the slope, negative if down), and the absolute velocity of point C (positive if up the slope, negative if down) of the cable. 24° Answers: VB/A = ft/sec ft/sec2 aB/A = Vc= ft/sec

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Topic: Connected Particles

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Under the action of force P, the constant acceleration of block B is 7.9 ft/sec? up the incline. For the instant when the velocity of B is 2.0 ft/sec up the incline, determine the velocity of B relative to A (positive if up the slope, negative if down), the acceleration of B relative to A (positive if up the slope, negative if down), and the absolute velocity of point C (positive if up the slope, negative if down) of the cable. 24° Answers: VB/A = ft/sec AB/A = ft/sec2 Vc = ft/sec
Transcribed Image Text:Under the action of force P, the constant acceleration of block B is 7.9 ft/sec? up the incline. For the instant when the velocity of B is 2.0 ft/sec up the incline, determine the velocity of B relative to A (positive if up the slope, negative if down), the acceleration of B relative to A (positive if up the slope, negative if down), and the absolute velocity of point C (positive if up the slope, negative if down) of the cable. 24° Answers: VB/A = ft/sec AB/A = ft/sec2 Vc = ft/sec
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