Under the action of force P, the constant acceleration of block B is 6.6 ft/sec² up the incline. For the instant when the velocity of B is 2.6 ft/sec up the incline, determine the velocity of B relative to A (positive if up the slope, negative if down), the acceleration of B relative to A (positive if up the slope, negative if down), and the absolute velocity of point C (positive if up the slope, negative if down) of the cable. Answers: VB/A = aB/A = Vc = 19° i i i B P ! ft/sec ! ft/sec² ! ft/sec

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Under the action of force P, the constant acceleration of block B is 6.6 ft/sec² up the incline.
For the instant when the velocity of B is 2.6 ft/sec up the incline, determine the velocity of B
relative to A (positive if up the slope, negative if down), the acceleration of B relative to A
(positive if up the slope, negative if down), and the absolute velocity of point C (positive if up
the slope, negative if down) of the cable.
Answers:
VB/A =
aB/A =
Vc =
19°
i
i
i
B
P
! ft/sec
!
ft/sec²
! ft/sec
Transcribed Image Text:Under the action of force P, the constant acceleration of block B is 6.6 ft/sec² up the incline. For the instant when the velocity of B is 2.6 ft/sec up the incline, determine the velocity of B relative to A (positive if up the slope, negative if down), the acceleration of B relative to A (positive if up the slope, negative if down), and the absolute velocity of point C (positive if up the slope, negative if down) of the cable. Answers: VB/A = aB/A = Vc = 19° i i i B P ! ft/sec ! ft/sec² ! ft/sec
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