Under constant pressure P = 1 atm an ideal gas of 1.5 mol undergoes heating from 28°C to 128.0°C, and CV,m = 3/2R. Please calculate q, w, AU, and AH (all units are J). Instruction: Please enter all four answers using scientific notation (E notation) with three significant figures, such as 2.30E4 (=23000). If the answer is negative, please do not forget the negative sign. If answer is zero, please just enter 0 without decimal. (1) q= (2) w= (3) AU= (4) ΔΗ=
Under constant pressure P = 1 atm an ideal gas of 1.5 mol undergoes heating from 28°C to 128.0°C, and CV,m = 3/2R. Please calculate q, w, AU, and AH (all units are J). Instruction: Please enter all four answers using scientific notation (E notation) with three significant figures, such as 2.30E4 (=23000). If the answer is negative, please do not forget the negative sign. If answer is zero, please just enter 0 without decimal. (1) q= (2) w= (3) AU= (4) ΔΗ=
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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15
Transcribed Image Text:QUESTION 15
Under constant pressure P = 1 atm an ideal gas of 1.5 mol undergoes heating from 28°C to 128.0°C, and CV,m = 3/2R.
Please calculate q, w, AU, and AH (all units are J).
Instruction: Please enter all four answers using scientific notation (E notation) with three significant figures, such as
2.30E4 (=23000). If the answer is negative, please do not forget the negative sign. If answer is zero, please just enter 0
without decimal.
(1) q=
(2) w=
(3) AU=
(4) ΔΗ=
Expert Solution
Step 1
Given Details:
At constant Pressure , Gas is being heated
P=1 atm
no. of moles of gas ,n=1.5 mol
Initial Temperature, T1=280C=28+273=301 K
Final Temperature, T2=128.00C=128.0+273=401 K
Cv,m=3R/2
we need to determine the q,W,∆U and ∆H.
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