Under certain conitions, the number of diseased cells N ( t ) at time t increases at a rate N ' ( t ) = A e kt , where A is the rate of increase at time 0 ( in cells per day ) and k is a constant. a. Suppose A = 50, and at 4 days, the cells are growing at a rate of 200 per day. Find a formula for the number of cells after t days, given that 300 cells are present at t = 0. b. Using the answer from part a, how many cells are present after 9 days?
Under certain conitions, the number of diseased cells N ( t ) at time t increases at a rate N ' ( t ) = A e kt , where A is the rate of increase at time 0 ( in cells per day ) and k is a constant. a. Suppose A = 50, and at 4 days, the cells are growing at a rate of 200 per day. Find a formula for the number of cells after t days, given that 300 cells are present at t = 0. b. Using the answer from part a, how many cells are present after 9 days?
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter5: Inverse, Exponential, And Logarithmic Functions
Section5.6: Exponential And Logarithmic Equations
Problem 64E
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Under certain conitions, the number of diseased cells N ( t ) at time t increases at a rate N ' ( t ) = A e kt , where A is the rate of increase at time 0 ( in cells per day ) and k is a constant.
a. Suppose A = 50, and at 4 days, the cells are growing at a rate of 200 per day. Find a formula for the number of cells after t days, given that 300 cells are present at t = 0.
b. Using the answer from part a, how many cells are present after 9 days?
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