Under certain conditions the rate of this reaction is zero order in hydrogen iodide with a rate constant of 0.0070 M's : 2 HI (g) → H, (g) + I, (g) Suppose a 2.0 L flask is charged under these conditions with 100. mmol of hydrogen iodide. How much is left 2.0 s later? You may assume no other reaction is important. Be sure your answer has a unit symbol, if necessary, and round it to 2 significant digits.
Under certain conditions the rate of this reaction is zero order in hydrogen iodide with a rate constant of 0.0070 M's : 2 HI (g) → H, (g) + I, (g) Suppose a 2.0 L flask is charged under these conditions with 100. mmol of hydrogen iodide. How much is left 2.0 s later? You may assume no other reaction is important. Be sure your answer has a unit symbol, if necessary, and round it to 2 significant digits.
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Under certain conditions the rate of this reaction is zero order in hydrogen iodide with a rate constant of 0.0070 M's :
2 HI (g) → H, (g) + I, (g)
Suppose a 2.0L flask is charged under these conditions with 100. mmol of hydrogen iodide. How much is left 2.0 s later? You may
assume no other reaction is important.
olo
Be sure your answer has a unit symbol, if necessary, and round it to 2 significant digits.
Ar
x10"
Transcribed Image Text:- 1
Under certain conditions the rate of this reaction is zero order in hydrogen iodide with a rate constant of 0.0070 M's :
2 HI (g) → H, (g) + I, (g)
Suppose a 2.0L flask is charged under these conditions with 100. mmol of hydrogen iodide. How much is left 2.0 s later? You may
assume no other reaction is important.
olo
Be sure your answer has a unit symbol, if necessary, and round it to 2 significant digits.
Ar
x10
Expert Solution

Step 1
A zero order reaction is the independent of the reactant concentration.
And formula used
[A]t = - kt + [A]0
Where [A]t is concentration of HI after 2.0 s.
k = rate constant = 0.0070 M.s-1 .
and t = time = 2.0 s; and
[A]0 = Initial concentration of HI = 100.0 × 10-3 moles / 2.0 L = 0.05 M
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