Ultimately, we wish to find the solution(s) to the following system of equations. 4x - 5y = 15 0.8x y = -3 First, we will graph each equation by hand using the slope-intercept form of an equation, y = mx + b, where y is the dependent variable and x is the independent variable. Write the first equation in slope-intercept form. 4x - 5y = 15 - 5y = y = x- Write the second equation in slope-intercept form. 0.8x - y = -3 -y = y = y = + 15 5 3 x + 3 +3
Ultimately, we wish to find the solution(s) to the following system of equations. 4x - 5y = 15 0.8x y = -3 First, we will graph each equation by hand using the slope-intercept form of an equation, y = mx + b, where y is the dependent variable and x is the independent variable. Write the first equation in slope-intercept form. 4x - 5y = 15 - 5y = y = x- Write the second equation in slope-intercept form. 0.8x - y = -3 -y = y = y = + 15 5 3 x + 3 +3
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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Question
Write the first equation in slope-intercept form
writr the second equation in slope-intercept form

Transcribed Image Text:Ultimately, we wish to find the solution (s) to the following system of equations.
4x - 5y = 15
0.8x – y = -3
First, we will graph each equation by hand using the slope-intercept form of an equation, y = mx + b, where y is the
dependent variable and x is the independent variable.
Write the first equation in slope-intercept form.
4x - 5y = 15
- 5y =
y =
-y =
y =
4
Write the second equation in slope-intercept form.
0.8x y = -3
y =
x + =
5
+ 15
- 3
x + 3
x + 3
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