ugh sample). Also, I have given you ation for a when n is large, and there ximate large sample confidence inter . (b), and (c), below (Circle the co the point estimate, compute th formula-if you use Excel or s nd to two decimal places. fidence interval for the population =) (24.31, 27.49) (iii) (2
ugh sample). Also, I have given you ation for a when n is large, and there ximate large sample confidence inter . (b), and (c), below (Circle the co the point estimate, compute th formula-if you use Excel or s nd to two decimal places. fidence interval for the population =) (24.31, 27.49) (iii) (2
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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![1. A random sample of 90 observations produced a sample mean of of = 25.9 and a sample standard deviation
of s = 2.7. Note that since n = 90 > 30, we can assume normality due the CLT (using our rule of thumb that
n 2 30 is considered a large enough sample). Also, I have given you a rule of thumb for large samples that says
s is considered a good approximation for a when n is large, and therefore we may use r 8/i in combination
with the z-distribution to approximate large sample confidence intervals for u, even when o is unknown. Follow
these rules of thumb for parts (a), (b), and (c), below (Circle the correct answer but you must also SHOW
YOUR WORK, i.e., identify the point estimate, compute the margin of error, and write down the
complete confidence interval formula-if you use Excel or software, write down the functions you
use as well your inputs). Round to two decimal places.
(a) The approximate 90% confidence interval for the population mean u is
(i) (25.43, 26.37)
(ii) (24.31, 27.49)
(iii) (2.33, 3.07)
(iv) (25.00, 26.8)
>
(b) The approximate 95% confidence interval for the population mean u is
(i) (25.34, 26.46)
(ii) (24.22, 27.58)
(iii) (2.24, 3.16)
(iv) (24.01, 27.17)
(c) The approximate 99% confidence interval for the population mean µ is
(i) (25.17, 26.63)
(ii) (24.01, 27.79)
(iii) (2.03, 3.37)
(iv) (23.80, 27.38)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3617dcdb-38b0-4509-9fd9-c5e9a4205d16%2F0377080d-a53c-4f82-b3fd-700cf85bfb63%2F7slr73_processed.jpeg&w=3840&q=75)
Transcribed Image Text:1. A random sample of 90 observations produced a sample mean of of = 25.9 and a sample standard deviation
of s = 2.7. Note that since n = 90 > 30, we can assume normality due the CLT (using our rule of thumb that
n 2 30 is considered a large enough sample). Also, I have given you a rule of thumb for large samples that says
s is considered a good approximation for a when n is large, and therefore we may use r 8/i in combination
with the z-distribution to approximate large sample confidence intervals for u, even when o is unknown. Follow
these rules of thumb for parts (a), (b), and (c), below (Circle the correct answer but you must also SHOW
YOUR WORK, i.e., identify the point estimate, compute the margin of error, and write down the
complete confidence interval formula-if you use Excel or software, write down the functions you
use as well your inputs). Round to two decimal places.
(a) The approximate 90% confidence interval for the population mean u is
(i) (25.43, 26.37)
(ii) (24.31, 27.49)
(iii) (2.33, 3.07)
(iv) (25.00, 26.8)
>
(b) The approximate 95% confidence interval for the population mean u is
(i) (25.34, 26.46)
(ii) (24.22, 27.58)
(iii) (2.24, 3.16)
(iv) (24.01, 27.17)
(c) The approximate 99% confidence interval for the population mean µ is
(i) (25.17, 26.63)
(ii) (24.01, 27.79)
(iii) (2.03, 3.37)
(iv) (23.80, 27.38)
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