electircal circuit 2 uctor voltage, which is left as an exercise for the reader.1 kPRACTICE= 40 cos 8000t V in the circuit of Fig. 10.7. Use10.3 Let v,Thévenin's theorem where it will do the most good, and find the valueat t =0 for (a) iL; (b) v; (c) ir: (d) i..3 kn100 mHAns: 18.71 mA; 15.97 V: 5.32 mA: 24.0 mA.IFIGURE 10.7ll

Given circuit in time domain is, Convert the time domain circuit into frequency domain: Given…

uctor voltage, which is left as an exercise for the reader. 1 kN PRACTICE 10.3 Let v, = 40 cos 8000t V in the circuit of Fig. 10.7. Use 3 kn 100 mH Thévenin's theorem where it will do the most good, and find the value at t =0 for (a) iL: (b) v; (c) ir: (d) i. Ans: 18.71 mA; 15.97 V; 5.32 mA: 24.0 mA. IFIGURE 10.7 el

uctor voltage, which is left as an exercise for the reader. 1 kN PRACTICE 10.3 Let v, = 40 cos 8000t V in the circuit of Fig. 10.7. Use 3 kn 100 mH Thévenin's theorem where it will do the most good, and find the value at t =0 for (a) iL: (b) v; (c) ir: (d) i. Ans: 18.71 mA; 15.97 V; 5.32 mA: 24.0 mA. IFIGURE 10.7 el

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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