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Ube V BE UBE -5 V/V 5 V/V 200 V/V 20 V/V )-200 V/V ic Vcc Rc UCE

Ube V BE UBE -5 V/V 5 V/V 200 V/V 20 V/V )-200 V/V ic Vcc Rc UCE

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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**BJT Single Transistor Common-Emitter Amplifier** The given problem provides details about a BJT single transistor common-emitter amplifier with the following specifications: - Supply Voltage (\(V_{CC}\)) = 20 volts - Collector Current (\(I_C\)) = 5 mA - Collector Resistor (\(R_C\)) = 1 kΩ - Thermal Voltage (\(V_T\)) = 25 mV **Objective:** Calculate the expected small signal voltage gain (\(v_{ce}/v_{be}\)). **Circuit Diagram Explanation:** The diagram illustrates a common-emitter amplifier: 1. **Power Supply:** The circuit is powered by a voltage source, \(V_{CC}\), of 20 volts connected to the collector through the resistor \(R_C\). 2. **Transistor:** The bipolar junction transistor (BJT) is configured with the collector connected to the \(R_C\), the emitter grounded, and the base connected to the input signal. 3. **Input Signal:** The small signal \(v_{be}\) represents the input voltage across the base-emitter junction with a larger DC bias voltage \(V_{BE}\). 4. **Output Voltage:** The output voltage \(v_{ce}\) is taken across the collector-emitter junction. **Possible Answers:** The potential answers for the voltage gain are: - \(-5 \, \text{V/V}\) - \(5 \, \text{V/V}\) - \(200 \, \text{V/V}\) - \(20 \, \text{V/V}\) - \(-200 \, \text{V/V}\) - \(-20 \, \text{V/V}\) **Calculating Voltage Gain:** The voltage gain (\(A_v\)) for a common-emitter amplifier can be determined using: \[ A_v = -\frac{R_C}{r_e} \] Where \(r_e\) is the emitter resistance and can be approximated by: \[ r_e \approx \frac{V_T}{I_C} \] Substitute the given values: \[ r_e \approx \frac{25 \, \text{mV}}{5 \, \text{mA}} = 5 \, \Omega \] Then, calculate the voltage gain: \[ A_v = -\frac{1000 \, \Omega}{5 \
Transcribed Image Text:**BJT Single Transistor Common-Emitter Amplifier** The given problem provides details about a BJT single transistor common-emitter amplifier with the following specifications: - Supply Voltage (\(V_{CC}\)) = 20 volts - Collector Current (\(I_C\)) = 5 mA - Collector Resistor (\(R_C\)) = 1 kΩ - Thermal Voltage (\(V_T\)) = 25 mV **Objective:** Calculate the expected small signal voltage gain (\(v_{ce}/v_{be}\)). **Circuit Diagram Explanation:** The diagram illustrates a common-emitter amplifier: 1. **Power Supply:** The circuit is powered by a voltage source, \(V_{CC}\), of 20 volts connected to the collector through the resistor \(R_C\). 2. **Transistor:** The bipolar junction transistor (BJT) is configured with the collector connected to the \(R_C\), the emitter grounded, and the base connected to the input signal. 3. **Input Signal:** The small signal \(v_{be}\) represents the input voltage across the base-emitter junction with a larger DC bias voltage \(V_{BE}\). 4. **Output Voltage:** The output voltage \(v_{ce}\) is taken across the collector-emitter junction. **Possible Answers:** The potential answers for the voltage gain are: - \(-5 \, \text{V/V}\) - \(5 \, \text{V/V}\) - \(200 \, \text{V/V}\) - \(20 \, \text{V/V}\) - \(-200 \, \text{V/V}\) - \(-20 \, \text{V/V}\) **Calculating Voltage Gain:** The voltage gain (\(A_v\)) for a common-emitter amplifier can be determined using: \[ A_v = -\frac{R_C}{r_e} \] Where \(r_e\) is the emitter resistance and can be approximated by: \[ r_e \approx \frac{V_T}{I_C} \] Substitute the given values: \[ r_e \approx \frac{25 \, \text{mV}}{5 \, \text{mA}} = 5 \, \Omega \] Then, calculate the voltage gain: \[ A_v = -\frac{1000 \, \Omega}{5 \
Expert Solution
Step 1: we need to determine small signal voltage gain vce/vbe

Given that, 

                                 Electrical Engineering homework question answer, step 1, image 1

                                          Vcc =20v

                                Collector current Ic = 5mA

                                Collector resistor Rc = 1kcapital omega

                                Voltage VT = 25mV

                                 Voltage gain v subscript c e end subscript over v subscript b e end subscript space equals ?


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