U2 in the circuit shown in Fig. 2.43. Also calculate 1 and iz and the power dissipated in the 12-N and 40-2 resistors. Answer: vi = 5 V, i 250 mA, p2 = 2.5 W. = 416.7 mA, P1 = 2.083 W, U2 = 10 V, i2 = %3D %3D 12 2 + Figure 2.43 For Practice Prob. 2.12. 10 2 40 15 V ww ww
U2 in the circuit shown in Fig. 2.43. Also calculate 1 and iz and the power dissipated in the 12-N and 40-2 resistors. Answer: vi = 5 V, i 250 mA, p2 = 2.5 W. = 416.7 mA, P1 = 2.083 W, U2 = 10 V, i2 = %3D %3D 12 2 + Figure 2.43 For Practice Prob. 2.12. 10 2 40 15 V ww ww
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Transcribed Image Text:Vi and v2 in the circuit shown in Fig. 2.43. Also calculate iı and
i2 and the power dissipated in the 12-N and 40-2 resistors.
Answer: U1 = 5 V, i = 416.7 mA, p1 = 2.083 W, v2 =
250 mA, p2 = 2.5 W.
10 V, i2 =
12 2
ww
Figure 2.43
For Practice Prob. 2.12.
10 2
40 2
15 V
ww
ww
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