у EXAMPLE 7 Find the critical numbers of the function. 7.6 x3/5(5 x) f(x) The Product Rule gives the following. SOLUTION d 5 dx d 5 ) (5 x) f'(x) = x3/5 -X dx 35 - х) -1 -X 5х -5x 3(5 x) 5х () Video Example 15 [The same result could be obtained by first writing f(x) = 5x3/5 - x8/5.] Therefore f '(x) = 0 if (15 — 8х) = 0, that is, x =15/8 and f'(x) does not exist when x = 0 5х (larger) and 15/8 Thus the critical numbers are 15/8 (smaller)

Calculus: Early Transcendentals
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Chapter1: Functions And Models
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EXAMPLE 7
Find the critical numbers of the function.
7.6
x3/5(5 x)
f(x)
The Product Rule gives the following.
SOLUTION
d
5
dx
d
5
)
(5 x)
f'(x) = x3/5
-X
dx
35 - х)
-1
-X
5х
-5x
3(5 x)
5х
()
Video Example
15
[The same result could be obtained by first writing f(x) = 5x3/5 - x8/5.] Therefore f '(x) = 0 if
(15 — 8х)
= 0, that is, x =15/8
and f'(x) does not exist when x = 0
5х
(larger) and 15/8
Thus the critical numbers are 15/8
(smaller)
Transcribed Image Text:у EXAMPLE 7 Find the critical numbers of the function. 7.6 x3/5(5 x) f(x) The Product Rule gives the following. SOLUTION d 5 dx d 5 ) (5 x) f'(x) = x3/5 -X dx 35 - х) -1 -X 5х -5x 3(5 x) 5х () Video Example 15 [The same result could be obtained by first writing f(x) = 5x3/5 - x8/5.] Therefore f '(x) = 0 if (15 — 8х) = 0, that is, x =15/8 and f'(x) does not exist when x = 0 5х (larger) and 15/8 Thus the critical numbers are 15/8 (smaller)
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