u 341 Sin 6.45 + Sin 26.6 az 05.20 B = 65° 40' b= 6.38 in C= 3.28. 2 and Sides 1 find all for both triangles

Elementary Geometry For College Students, 7e
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ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
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Find all possible solutions for the triangle (should only be 2)
**Triangle Problem Solving**

Given data:

1. Angle A = 60° 43'
2. Side a = 85.20
3. Side b = 60.3
4. Angle B = 65° 40'

Angles and sides to find:

- **Angle C**
- **Side c** (for both triangles)

Using the Law of Sines:

\[
\frac{a}{\sin A} = \frac{b}{\sin B} = \frac{c}{\sin C}
\]

Calculate values:

1. Calculate angle C using: 
   \[ C = 180° - (A + B) \]

2. Use the Law of Sines to find side c:
   \[ c = \frac{a \cdot \sin C}{\sin A} \]

Repeat calculations if necessary for different angles C that satisfy the given conditions. 

**Note:** The problem involves finding all sides for two possible configurations of the triangle (ambiguous case in trigonometry).
Transcribed Image Text:**Triangle Problem Solving** Given data: 1. Angle A = 60° 43' 2. Side a = 85.20 3. Side b = 60.3 4. Angle B = 65° 40' Angles and sides to find: - **Angle C** - **Side c** (for both triangles) Using the Law of Sines: \[ \frac{a}{\sin A} = \frac{b}{\sin B} = \frac{c}{\sin C} \] Calculate values: 1. Calculate angle C using: \[ C = 180° - (A + B) \] 2. Use the Law of Sines to find side c: \[ c = \frac{a \cdot \sin C}{\sin A} \] Repeat calculations if necessary for different angles C that satisfy the given conditions. **Note:** The problem involves finding all sides for two possible configurations of the triangle (ambiguous case in trigonometry).
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