У (2х+1) x2+x dy 5) Consider the differential equation dx a) Find the general solution of the differential equation. b) Find the solution that satisfies the initial condition y(1) = 1

Q: could you explain the steps you took to get there ?

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Q: Could you please provide another counter example a simpler one thank you!

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Q: Would you please explain step 2?

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Q: Hey can you go more in depth with this? Show step by step pls and thanks.

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Q: 40 20 15

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A: Please find the explanation below. Thank you

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A: i have question 9 for next question repost

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Q: C. Domain Range D. Domain Range

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A: Given:     a+b+c=0           ...(1)a2+b2+c2=1           ...(2)a4+b4+c4=?

Q: Can you please evaluate part IV and V? Can part b and c also be completed?

A: We have find the integral of  4) ∫x4 exdx5) ∫x5 exdx

Q: tell why other options are not correct

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A: The answer is given below

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A: Solve the given problem.

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A: Taking the results from your answer

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A: The given question can be solved as shown in step2.

Q: 1. Simplify: - 8x - 5 4x- 25 4x 4х - 4 x-1

A: abcd = ab×dc

Q: X = 45 24 30 y = y z = O Ging Wilson (Ali Things Algebra®, LLC), 2014-2018

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Q: cleared

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Q: Explain again step 3 ? I don't understand.

A: It is clear that the function f(t) has jump discontinuity at (n,0) where n is an integer.