U 0-29x t逆-10 =D5x Find derivative Cay Idx

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Find the derivative dy/dx

The image contains a handwritten mathematical expression and a task. The expression is:

\[ y = 5x^3 - 2\sqrt{x} + x^{\frac{1}{3}} - 10 \]

The task is:

"Find derivative (dy/dx)"

To solve this, apply the rules of differentiation to each term separately:

- The derivative of \(5x^3\) is \(15x^2\).
- The derivative of \(-2\sqrt{x}\) is \(-2 \cdot \frac{1}{2}x^{-\frac{1}{2}} = -x^{-\frac{1}{2}}\).
- The derivative of \(x^{\frac{1}{3}}\) is \(\frac{1}{3}x^{-\frac{2}{3}}\).
- The derivative of the constant \(-10\) is \(0\).

Thus, the derivative \(\frac{dy}{dx}\) is:

\[ \frac{dy}{dx} = 15x^2 - x^{-\frac{1}{2}} + \frac{1}{3}x^{-\frac{2}{3}} \]

This transcription and explanation can be used to guide students through the process of finding the derivative of a polynomial and radical expression.
Transcribed Image Text:The image contains a handwritten mathematical expression and a task. The expression is: \[ y = 5x^3 - 2\sqrt{x} + x^{\frac{1}{3}} - 10 \] The task is: "Find derivative (dy/dx)" To solve this, apply the rules of differentiation to each term separately: - The derivative of \(5x^3\) is \(15x^2\). - The derivative of \(-2\sqrt{x}\) is \(-2 \cdot \frac{1}{2}x^{-\frac{1}{2}} = -x^{-\frac{1}{2}}\). - The derivative of \(x^{\frac{1}{3}}\) is \(\frac{1}{3}x^{-\frac{2}{3}}\). - The derivative of the constant \(-10\) is \(0\). Thus, the derivative \(\frac{dy}{dx}\) is: \[ \frac{dy}{dx} = 15x^2 - x^{-\frac{1}{2}} + \frac{1}{3}x^{-\frac{2}{3}} \] This transcription and explanation can be used to guide students through the process of finding the derivative of a polynomial and radical expression.
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Given function is y=5x3-2x3+x42-10

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