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- An important indicator of lung function is forced expiratory volume (FEV), which is the volume of air that a person can expire in one second. Dr. Hernandez plans to measure FEV in a random sample of n individuals from a certain population, and to use the sample mean to estimate of the population mean. The population distribution of FEV is assumed to be normal with mean mu-3000 ml and SD sigma=400 ml. Which of the following statements is correct regarding the sampling distribution of the sample mean? Ⓒa. It is the theoretical distribution of a sample statistic (in this case the sample mean). b. It is the theoretical distribution of all individuals in the population. Oc It is the observed distribution of all individuals in the sample. QUESTION 2 Suppose sample size is n-64. What is the mean of the sampling distribution of y? Ⓒa.50 b.375 c400 Od 3000At ? = 0.10, can it be concluded that there is a difference in means of hours spentfor studying between male and female based on point estimate in second attached image?Assume the population variances are unequalDo the mean weights of male college freshmen and male college seniors differ? There are arguments for and against this question. The mean weight, μx of college freshmen will be compared to the mean weight, My of college seniors. The true values of Mx and My are unknown. It is recognized that the true standard deviations are x = 13 for male college freshmen and dy = 24 for male college seniors. We take a random sample of m = 431 college freshmen and a random sample of n=289 college seniors. The mean weights were x = 178 for male college freshmen and y = 185 for male college seniors. Assuming independence between the samples and assuming the weights are normally distributed we would like to estimate My - My. a) What is the standard deviation of the distribution of x?[ b) What is the standard deviation of the distribution of x-y? c) Create a 95% confidence interval for Mx - Hy? d) What is the length of the confidence interval in part c) ? e) If we let n stay at 289 but vary m, what is the…
- A random sample of 100 observations from the first population was found to have a sample mean of 85 and a sample standard deviation of 10. A random sample of 80 observations from the second population was found to have a sample mean of 93 anc sample standard deviation of 15. At a = 0.01 level of significance, is there a difference the population means. Edit View Insert Format Tools Table 12pt v Paragraph v BIU O words ...The data in NutritionStudy include information on nutrition and health habits of a sample of 315 people. One of the variables is VitaminUse, indicating whether a person takes a multivitamin pill regularly or occasionally or not at all. Use technology to test whether the data provide evidence that the proportion taking a vitamin pill regularly is different from 35 % given. Clearly state the null and alternative hypotheses. : : 42 : Pi : P2 :: 0.35 : 2 :: P1 : p2 :: :: r Ho: vs Hg: ::If the Ʃ(Xi- X')2 is equal 17.72 for the following reading 110, 112, 107, 109, 111, 108, 110 Calculate: 1-the standard deviation 2-the variance 3-the relative standard deviation 4-Cofficent of variation 5-Standard deviation of the mean
- QUESTION 9 A population has a standard deviation of 8. What is the minimum sample size needed to estimate a mean to within 2 units with 66.8% confidence? O A. 13 ОВ. 15 ОС. 14 O D. 12 O E. 16 QUESTION 10 A sample of 40 is taken from a population where the population standard deviation is known to be 5. What z should be used for an 78.7% confiden 'a12 estimate of the mean, rounded to five decimal places? O A. 1.24518 O B. 1.24526 OC1 24541 DELL F10 F8 Esc F6 F7 F4 F5 F3 # 2$ % 7 3 4a distribution with a mean of u=41 and a standard deviation of 4 is transformed into a standardized distribution with a mean of u=100 and a standardized deviation =20, find the new standardized score for each of the following values from the original population, x=39, x=36, x=45, x=50Suppose there are two different vaccines for Covid, Vaccine X and Vaccine Y. An interesting question recipients on vaccine Y. The vaccine X recipients had a mean 6AEQ of x = 151. The vaccine Y recipients had a mean 6AEQ of y = 148. It is recognized that the true standard deviation of 6AEQ for vaccine X recipients is o, = 9.7 while it is recognized that the true standard deviation of 6AEQ for vaccine Y recipients is o, = 10.5. The true (unknown) mean 6AEQ for vaccine X recipients is ly, while the true (unknown) mean 6AEQ for vaccine Y recipients is ,. 6AEQ measurements are known to be a normally distributed. In summary: swhich vaccine has a higher 6-month antibody effectiveness quotient (6AEQ). To examine this we randomly select 78 recipients of vaccine X and 93 Type Sample Size Sample Mean Standard Deviation Vaccine X78 151 9.7 Vaccine Y93 148 10.5 1 Calculate the standard deviation of X- Y? ) If we wish to create an 96% confidence interval for uy - uy then what is the z critical value…
- A hypertension trial is mounted, and 12 participants are randomly assigned to receive either a new medication or a placebo. Each participant takes the assigned medication and their systolic blood pressure, in mm Hg, is recorded after 6 months on the assigned medication. The data are shown in Table 7..9. Is there a difference in mean systolic blood pressure between treatments? Run the appropriate test at α = 0.05. PLEASE SHOW THE ANSWER IN EXCEL FORMAT WITH FORMULAS.2ri 19-24. It is known that the mean diameters of rivets produced by two firms A and B are practically the same but the standard deviations may differ. For 22 rivets produced by firm A, the ståndard deviation is 2-9 mm. while for 16 rivets manufactured by firm B, the standard deviation is 3-8 mm. Compute the statistic you would use to test whether the products of firm A have the same variability as those of firm B and test its significance. i Jutiey W- ne.