ty" + (5t- 1)y'- 5y= 61? e -5t. -5t y, = 5t- 1, y2 =e A general solution is y(t)=

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ISBN:9780470458365
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Use the variation of parameters to find a general solution to the differential equation given that the functions y1 and y2 are linearly independent solutions to the corresponding homogeneous equation for t>0 A general solution is y(t)=
ty" + (5t-1)y'- 5y = 61 e -5t.
y, = 5t- 1,
Y2 =e -5t
A general solution is y(t) =
Transcribed Image Text:ty" + (5t-1)y'- 5y = 61 e -5t. y, = 5t- 1, Y2 =e -5t A general solution is y(t) =
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