ty'' +(2t - 1)y' - 2y = 5t² e -2t. A general solution is y(t) = Y₁ = 2t - 1, Y₂=e-2t
ty'' +(2t - 1)y' - 2y = 5t² e -2t. A general solution is y(t) = Y₁ = 2t - 1, Y₂=e-2t
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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use variation of parameters to finda general solution to the differntial equation given the function y1 and y2 are linearly independent solutions to the corresponding homogenous equation for t>0
Transcribed Image Text:ty"' + (2t - 1)y' - 2y = 5t² e -2t.
A general solution is y(t) =
Y₁ = 2t - 1,
Y₂=e-2t
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