TXח In the next video, we will talk about a particle confined to a box. We will see the wavefunction for this particle is w(x) = where a is the a sin length of the box and n= 1.2.3.... Use the Schrödinger equation to calculate the kinetic energy for this particle. (Assume the potential energy - and therefore the potential energy operator - is zero.) E = a' E = a E= - 2ma n?n?n? E = 2ma? n?n?n? E= - 2ma?

Chemistry
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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2
sin
a
In the next video, we will talk about a particle confined to a box. We will see the wavefunction for this particle is
w(x) =.
where a
is the
length of the box and n= 1.2.3.... Use the Schrödinger equation to calculate the kinetic energy for this particle. (Assume the potential energy - and
therefore the potential energy operator - is zero.)
n²n?
E=
a
E=
a
E=
2 ma
n²n²n?
E =-
2ma?
n²n?n?
22
E=
2ma?
E =
2ma
Transcribed Image Text:2 sin a In the next video, we will talk about a particle confined to a box. We will see the wavefunction for this particle is w(x) =. where a is the length of the box and n= 1.2.3.... Use the Schrödinger equation to calculate the kinetic energy for this particle. (Assume the potential energy - and therefore the potential energy operator - is zero.) n²n? E= a E= a E= 2 ma n²n²n? E =- 2ma? n²n?n? 22 E= 2ma? E = 2ma
Expert Solution
Step 1

The energy of a particle confined in a 1D box is given by,

E=n2h28ma2

where a is edge length of the box.

 

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